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MariettaO [177]
3 years ago
6

How can csc^2-cot^2 = 1?

Mathematics
1 answer:
Softa [21]3 years ago
6 0

ANSWER

By simplifying the left hand side using the Pythagorean Identity.

EXPLANATION

The given identity is

\csc^{2} (x) -  \cot^{2} (x) = 1

Take the left hand side and simplify to get the right hand side.

\csc^{2} (x) -  \cot^{2} (x) =  \frac{1}{\sin^{2} (x)}  - \frac{ \cos^{2} (x)}{\sin^{2} (x)}

Collect LCM for the denominators.

\csc^{2} (x) -  \cot^{2} (x) =  \frac{1 -  \cos^{2} (x)}{\sin^{2} (x)}

Recall the Pythagorean Identity.

\cos^{2} (x) +  \sin^{2} (x) = 1

This implies that:

1 -  \cos^{2} (x) =  \sin^{2} (x)

We substitute this to get,

\csc^{2} (x) -  \cot^{2} (x) =  \frac{\sin^{2} (x)}{\sin^{2} (x)}

\csc^{2} (x) -  \cot^{2} (x) = 1

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students were grouped into 4 classrooms with an average of 33.5 students per classroom. if the students were regrouped into 5 cl
erma4kov [3.2K]

Answer:

26.8

Step-by-step explanation:

Because 33.5 was the average of how many students were in a classroom (if there were 4 classrooms), then 33.5 is can somewhat be the average of how many students were in one classroom; 1/4 of the classrooms can hold an average of 33.5.

Total students that were divided into 4 classrooms :

33.5 × 4 = 134

So if there is 134 students that will be grouped into 5 different classrooms, divide 134 by 5 to find the average amount of students that will be grouped.

134 ÷ 5 = 26.8

So, the average amount of students that will be grouped if they were divided into 5 classrooms would be 26.8 .

Hope this helped !

4 0
2 years ago
Tran checked the time on his watch after he finished his daily run select the time that Tran finished running mark all that appl
Viefleur [7K]

Answer:

(a) and (b) are correct

Step-by-step explanation:

Given

See attachment for complete question

Required

Select the correct options

A clock is divided into two equal parts.

(1) 1 - 6

(2) 7 - 12

<em>When the hour hand is on (1), then the time is "after"</em>

<em>When the hour hand is on (2), then the time is "before"</em>

<em />

From the attached clock, we have:

(1) The hour hand on 9

(2) The minute hand 1 unit above 9 i.e. 46 minutes

(1) implies that, the time is before 9 i.e. past 8

(2) implies that the minutes is (60 - 46) before 9 or 46 minutes after 8

In (1) and (2) above, we have two interpretations.

1: (60 - 46) minutes before 9

This gives:

14 minutes before 9

2: 46 minutes past 8

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3 0
2 years ago
(ab^2 x -b^4a^3)^2<br><br> What is the answers
Umnica [9.8K]

Answer:

\left(ab^2x-b^4a^3\right)^2:\quad a^2b^4x^2-2a^4b^6x+a^6b^8

Step-by-step explanation:

Given the expression

\left(ab^2\:x\:-b^4a^3\right)^2

solving the expression

\left(ab^2\:x\:-b^4a^3\right)^2

\mathrm{Apply\:Perfect\:Square\:Formula}:\quad \left(a-b\right)^2=a^2-2ab+b^2

a=ab^2x,\:\:b=b^4a^3

so the expression becomes

=\left(ab^2x\right)^2-2ab^2xb^4a^3+\left(b^4a^3\right)^2

=a^2b^4x^2-2a^4b^6x+a^6b^8

Thus,

\left(ab^2x-b^4a^3\right)^2:\quad a^2b^4x^2-2a^4b^6x+a^6b^8

3 0
2 years ago
In the function f(t) = sin(t), what is the effect of multiplying t by a coefficient of 2?
liubo4ka [24]

Answer:

"changes the period to pi"

Step-by-step explanation:

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Here, t is the period, by definition.

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Multiplying t by a number that is between 0 and 1 makes the period expanded.

For the first, if we multiply the period by a, the period becomes \frac{2\pi}{a}

Since the problem tells us to multiply by 2, we know the period becomes compressed and becomes :

\frac{2\pi}{2}=\pi

Third answer choice is right.

5 0
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blondinia [14]

Answer:

b- 13 weeks

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She makes $550 a week but spends $200 on merchandise so her total weekly is technically $350 in order to earn profit she has to get more than $4500

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