Answer:
<h3>The option C) 15 s is correct</h3><h3>Therefore the maximum height it reaches in <u>15 seconds. </u></h3>
Step-by-step explanation:
Given equation is 
Given that a projectile is thrown upward so that its distance above the ground after t seconds is 
<h3>To find how many seconds does it reach its maximum height:</h3>
"The standard form of a parabola's equation is expressed as :
.
If
, then the parabola opens upwards;
if
the parabola opens downwards."
The maximum height is the vertex of the parabola
which is
.
Comparing the given equation with the standard form of parabola we get
the values of a=-13 , b=390 and c=0
The maximum height in
.
Substitute the values we get



<h3>∴ t=15 s</h3><h3>∴ The option C) 15 s is correct.</h3><h3>∴ the maximum height is the vertex of the parabola, at t reaches in 15 seconds. </h3>
Answer:
-12x^2+42x-6
Step-by-step explanation:
Answer:
1
Step-by-step explanation:
3/9 + 2/3
Simplify the first fraction by dividing the top and bottom by 3
1/3 + 2/3
Since the denominators are the same, add the numerators
3/3
1
Answer:
87.1
Step-by-step explanation:
Lets say, first number = x
Second number = 3x+7
Total = 49
(x)+(3x+7)= 49
4x+7 = 49
4x = 42
x = 42/4
x= 10.5
x= 10.5
3x+7 = 3(10.5)+7 = 87.1
Hope this helps!!