Ok first of all, I EXTREMELY appreciate your use of parenthesis. Ok so first just raise both sides to the power of 1/2.
You'll see why I didn't include a negative. Then apply the log base 3/8 and you get
Then you split the log up and you get
You couldn't put a negative value for a log. That is why I excluded the negative part of the sqrt.
X/4 - 12 = -18
x/4 -12 +12 = -18 + 12
x/4 = -6
x/4 times 4 = -6 times 4
x = -24
Check
-24 divided by 4 = -6 -12 = -18
6n + 28 because the difference is 12 so if u half that to get the second it’s 6 hence 6n and then u have to add 6 to 22 to get 28 and it’s a positive number so therefore the expression is 6n+ 28
You can factor it into (-5m+n)(-5m+n)
Y = -1 is a horizontal line going through "-1" on the y axis
Note that the point (1,2) is exactly 3 units of distance above the line y = -1
When we reflect across this line, the point (1,2) will just move straight down to exactly 3 units of space below the line y = -1. Since we are not shifting left or right, the x coordinate of our original point will not change. The y coordinate of our original point will now need to be reduced by 6(3 units down to get to the line of reflection and then 3 more down to get to the image location)
The coordinates of the image point will be (1, -4)
Now we need to do the same process with (1, -4) being reflected across y=1
Note (1,-4) is 5 units of distance below the line y = 1 , so we need to reflect the point upward so that the image point is located exactly 5 units of distance above the line y = 1 Again, the x coordinate does not change, and our final image coordinates are (1, 6)
I guess more simply stated, if you're just looking for the number in the green box it would be " 1 " .. Reflecting points across horizontal lines only result in changes of the "y" coordinate since there is no shift left or right.
