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maw [93]
2 years ago
14

Phyllis invested 51000 dollars, a portion earning a simple interest rate of 4 percent per year and the rest earning a rate of 7

percent per year. After one year the total interest earned on these investments was 2370 dollars. How much money did she invest at each rate?
Mathematics
1 answer:
Liono4ka [1.6K]2 years ago
3 0

Answer:

Phyllis invested $11,000 at a simple interest rate of 7 percent per year and $40,000 at a simple interest rate of 4 percent per year.

Step-by-step explanation:

From the information provided, you can write the following equations:

x+y=51000 (1)

0.04x+0.07y=2370 (2), where

x is the portion earning a simple interest rate of 4 percent per year

y is the portion earning a simple interest rate of 7 percent per year

First, you can isolate x in (1):

x=51000-y (3)

Now, you can replace (3) in (2) and solve for y:

0.04(51000-y)+0.07y=2370

2040-0.04y+0.07y=2370

0.03y=330

y=330/0.03

y=11000

Then, you can replace the value of y in (3) to find the value of x:

x=51000-11000

x=40000

According to this, the answer is that Phyllis invested $11,000 at a simple interest rate of 7 percent per year and $40,000 at a simple interest rate of 4 percent per year.

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y = -2x + 19
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We gonna solve this system of equation by using the substitution method.

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Let start by substitute -2x + 19 for y in y = x + 7

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Answer:

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