Answer:
this could work y=(-22)x+41
96 divided by 6 is 16
96 divided by 8 is 12
96 divided by 12 is 8
96 divided by 16 is 6
96 divided by 32 is 3
Answer:
see explanation
Step-by-step explanation:
The sum to n terms of an arithmetic sequence is
= [ 2a₁ + (n - 1)d ]
where a₁ is the initial value and d the common difference
Given
= [ 10 + (n - 1)3 ]
Then by comparison
2a₁ = 10 ( divide both sides by 2 )
a₁ = 4 ← initial value
and d = 3 ← common difference
Thus
= [ 10 + (7 × 3) ]
= 4(10 + 21)
= 4 × 31
= 124
He would use 9 bills, and 5 coins. (fours $10, one $5, four $1. three quarters, one dime, and one penny). I calculated it all to make sure the total came out as 49.86