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PIT_PIT [208]
3 years ago
8

Find the perimeter and area of the figure.

Mathematics
2 answers:
Alexxx [7]3 years ago
8 0

Answer:

P: 26cm, A:36cm

Step-by-step explanation:

Remember, the perimeter of a rectangle is all of the sides added up. We already know the width is 4cm and the length is 9cm, and since the opposite sides are the same (the lenghts are the same size, the width are always the same size), we know that we have 2 4cm sides and 2 9cm sides.

Add: 4 + 4 + 9 + 9 and that is your perimeter.

The area is the length and width multiplied together:

Multiply: 9 x 4 and that is your area.

Jobisdone [24]3 years ago
5 0
The area is 36 and the perimeter is 26
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If x+ay =b and<br> ax-by=c <br> Then find out x , y . (with process)
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The solution of the given system of equations is,

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Step-by-step explanation:

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<em>x</em> + a<em>y</em> = b          .......(1)

a<em>x</em> - b<em>y</em> = c        .......(2)

We will use 'Substitution Method' to solve the given system of equations.

In this method, we will find out the value of either of the two variables that is '<em>x</em>' and '<em>y</em>' from one of the two equations in terms of the another variable  and then substitute that value in the other equation to find the value of the another variable.

Now, we will be finding out the value of '<em>x</em>' in terms of '<em>y</em>' from equation (1) and then substitute it in the equation (2).

Consider the equation (1), that is,

   <em>x</em> + a<em>y</em> = b ⇒ <em>x</em> = b - a<em>y</em>          ........(3)

Substitute the value of '<em>x</em>' from (3) in (2), we get

  a(b - a<em>y</em>) - b<em>y</em> = c

⇒ab - a²<em>y</em> - b<em>y</em> = c

⇒-a²<em>y</em> - b<em>y</em> = c - ab

⇒-<em>y</em>(a²+b) = c - ab

⇒<em>y</em>(a²+b) = ab - c

\implies y=\frac{ab-c}{a^{2}+b}

Now, substituting the above value of '<em>y</em>' in equation (3), we get

x=b-a(\frac{ab-c}{a^2+b})

\implies x=\frac{b(a^2+b)-a(ab-c)}{a^2+b}

\implies x=\frac{a^2b+b^2-a^2b+ac}{a^2+b}

\implies x = \frac{b^2+ac}{a^2+b}

Hence, the solution of the given system of equations is,

x = \frac{b^2+ac}{a^2+b} ;\; y = \frac{ab-c}{a^2+b}

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3 years ago
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