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LekaFEV [45]
2 years ago
7

Given that D( x ) = 2 x , select all of the following that are true statements.

Mathematics
2 answers:
TEA [102]2 years ago
8 0

Answer:

3rd

Step-by-step explanation:

ser-zykov [4K]2 years ago
6 0

Answer:

D(x) is a function. TRUE. It is a function of x.

x is the dependent variable. FALSE. x is the independent variable because the function is expressed in terms of the independent variable.

D(6) = 3. FALSE. D(6) = 2(6) = 12. D(6) should be equal to 12.

D(x) is a direct variation. TRUE. This holds true to the definition of direct variation where one variable is related to the other variable at the same constant multple. In this case, it is 2.

D(x) is a rule for the set of points (5, 10), (6, 12) and (-2, -4). TRUE. If you replace x with the first coordinate, the function would be equal to the corresponding second coordinate.

Step-by-step explanation:

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You deposit $300 in a savings account that pays 6% interest compounded semiannually. How much will you have at the middle of the
Makovka662 [10]

Answer:

  • The total amount accrued, principal plus interest,  from compound interest on an original principal of  $ 300.00 at a rate of 6% per year  compounded 2 times per year  over 0.5 years is $ 309.00.

  • The total amount accrued, principal plus interest,  from compound interest on an original principal of  $ 300.00 at a rate of 6% per year  compounded 2 times per year  over 1 year is $ 318.27.

Step-by-step explanation:

a)  How much will you have at the middle of the first year?

Using the formula

A\:=\:P\left(1+\frac{r}{n}\right)^{nt}

where

  • Principle = P
  • Annual rate = r
  • Compound = n
  • Time  = (t in years)
  • A = Total amount

Given:

Principle P = $300

Annual rate r = 6% = 0.06 per year

Compound n = Semi-Annually = 2

Time (t in years) = 0.5 years

To determine:

Total amount = A = ?

Using the formula

A\:=\:P\left(1+\frac{r}{n}\right)^{nt}

substituting the values

A=300\left(1+\frac{0.06}{2}\right)^{\left(2\right)\left(0.5\right)}

A=300\cdot \frac{2.06}{2}

A=\frac{618}{2}

A=309 $

Therefore, the total amount accrued, principal plus interest,  from compound interest on an original principal of  $ 300.00 at a rate of 6% per year  compounded 2 times per year  over 0.5 years is $ 309.00.

Part b) How much at the end of one year?

Using the formula

A\:=\:P\left(1+\frac{r}{n}\right)^{nt}

where

  • Principle = P
  • Annual rate = r
  • Compound = n
  • Time  = (t in years)
  • A = Total amount

Given:

Principle P = $300

Annual rate r = 6% = 0.06 per year

Compound n = Semi-Annually = 2

Time (t in years) = 1 years

To determine:

Total amount = A = ?

so using the formula

A\:=\:P\left(1+\frac{r}{n}\right)^{nt}

so substituting the values

A\:=\:300\left(1+\frac{0.06}{2}\right)^{\left(2\right)\left(1\right)}

A=300\cdot \frac{2.06^2}{2^2}

A=318.27 $

Therefore, the total amount accrued, principal plus interest,  from compound interest on an original principal of  $ 300.00 at a rate of 6% per year  compounded 2 times per year  over 1 year is $ 318.27.

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Answer:

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For a proportion of p =0.20, in order to ensure a standard error of 0.02, the sample size 'n' must be:

0.02 = 2.576*\sqrt{\frac{0.2*(1-0.2)}{n}}\\n=2,654.31

Rounding up to the next whole student, the sample size needed is 2,655 students.

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