For this case we have that by definition, a linear equation is of the form:
The variable (s) involved in the equation always have exponent 1.
Some examples of linear equations are:
Answer:
In a linear equation the variables have exponent 1.
-2(x + 3) = -2(x + 1) - 4
-2x - 6 = -2x - 2 - 4 <em>distributed -2 on the left and on the right</em>
-2x - 6 = -2x - 6
<u>+2x </u> <u>+2x </u>
-6 = -6
TRUE
Since this is a true statement, there are infinite solutions (aka All Real Numbers)
Answer: C
Answer:
d + c liters
Step-by-step explanation:
Answer:
10. 7n - 1 < -8
Isolate the variable, n. Do the opposite of PEMDAS. Treat the < as equal sign, what you do to one side, you do to the other. First, add 1 to both sides:
7n - 1 (+1) < - 8 (+1)
7n < - 8 + 1
7n < - 7
Isolate the variable, n. Divide 7 from both sides:
(7n)/7 < (-7)/7
n < -7/7
n < -1
n < -1 is your answer.
11. 3 > -7v + 4v
Combine like terms, then isolate the variable, v. First, add -7v and 4v together.
3 > (-7v + 4v)
3 > (4v - 7v)
3 > (-3v)
Isolate the variable, v. Divide -3 from both sides. Note that since you are dividing a negative number, you must flip the sign:
(3)/-3 > (-3v)/-3
3/-3 > v
-1 < v
v > -1 is your answer.
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Answer:
A.Both of the students did the problem correctly.
Step-by-step explanation:
B. Nikki multiplied the fraction(8/3) to the items in the parentheses. Then multiplied each side with 3. Jon did the opposite. He first removed the fraction by multiplying each side by 3. Then he multiplied 2 to the items in the paranthesis.
C. I prefer Jon's method. Fractions can be tricky. I prefer to remove them as soon as possible. This time the items in the paranthesis had whole numbers. But had any of them been a fraction too, the problem would have gotten a lot more tricky and it would very easy to make a mistake or miscalculate something.
