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seropon [69]
3 years ago
7

Cooper is at the grocery store buying lunch meat for a party. Ham costs $4.50 per pound and turkey costs $2.75 per pound. If Coo

per buys 4 pounds of ham and 3 pounds of turkey, how much will he spend in all?
Mathematics
2 answers:
MariettaO [177]3 years ago
7 0
H=4.50(4)
Ham=18
T=2.75(3)
Turkey=8.25
8.25+18= $26.25
Please give me the brainliest answer 
4vir4ik [10]3 years ago
4 0
$26.25 is the answer as 4 pounds of ham would be $18 and 3 pounds of turkey would cost $8.25


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The reciprocal parent function is translated 5 units right and 3 units up. Write an equation to represent the new function.
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Answer:

The new function is y=\frac{1}{x-5}+3 , where x ≠ 5

Step-by-step explanation:

The reciprocal parent function is f(x)=\frac{1}{x} , where x ≠ 0

The translation of f(x) to the right h units is f(x - h)

The translation of f(x) up k units is f(x) + k

The translation of f(x) to the right h units and up k units is f(x - h) + k

∵ The equation of the reciprocal parent function is  y=\frac{1}{x}

∵ The function is translated 5 units right

∴ h = 5

- That means 5 is subtracted from x ⇒ (x - 5)

∵ The function is  translated 3 units up

∴ k = 3

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Sarah would like to make a 6 lb nut mixture that is 60% peanuts and 40% almonds. She has several pounds of a mixture that is 80%
ivolga24 [154]

Answer:  

<em>a.  The system of equations that models the situation is....</em>

<em>     0.80x+0.50y=3.60\\\\ 0.20x+0.50y=2.40</em>

<em>b.  The solution to the system:  x = 2 and y = 4 </em>

<em>The amount of 80/20 mixture is 2 pounds and the amount of 50/50              mixture is 4 pounds.</em>

Step-by-step explanation:

Suppose, the amount of 80/20 mixture is  x pounds and the amount of 50/50 mixture is  y pounds.

So, the amount of peanuts in 80/20 mixture = 0.80x pound and the amount of almonds in 80/20 mixture =0.20x pound.

And the amount of peanuts in 50/50 mixture =0.50y pound and the amount of almonds in 50/50 mixture =0.50y pound.

Now, Sarah would like to make a 6 pounds nut mixture that is 60% peanuts and 40% almonds.

So, the amount of peanuts in that mixture =(6\times 0.60)=3.60 pounds

and the amount of almonds in that mixture =(6 \times 0.40)= 2.40 pounds.

So, the system of equations will be.........

0.80x+0.50y=3.60 ...................(1)\\\\ 0.20x+0.50y=2.40...................(2)

Subtracting equation (2) from equation (1), we will get.....

(0.80x+0.50y)-(0.20x+0.50y)=3.60-2.40\\ \\ 0.60x=1.20\\ \\ x= \frac{1.20}{0.60}=2

Now, plugging this x=2 into equation (1), we will get......

0.80(2)+0.50y=3.60\\ \\ 1.60+0.50y=3.60\\ \\ 0.50y=3.60-1.60=2\\ \\ y=\frac{2}{0.50}=4

So, the amount of 80/20 mixture is 2 pounds and the amount of 50/50 mixture is 4 pounds.

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