Question

1. The quality control manager at a light-bulb factory needs to estimate the mean life of a new type of light-bulb. The population standard deviation is assumed to be 60 hours. A random sample of 32 light-bulbs shows a sample mean life of 490 hours. Construct and explain a 95% confidence interval estimate of the population mean life of the new light-bulb.

Answer 1

Answer:

The 95% confidence interval estimate of the population mean life of the new light-bulb is (469.21 hours, 510.79 hours).

This confidence level means that we are 95% sure that the true population mean life of the new light bulb is in this interval.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$.

So it is z with a pvalue of $1-0.025 = 0.975$, so $z = 1.96$

Now we find M as such:

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the length of the sample. So:

$M = 1.96*\frac{60}{\sqrt{32}} = 20.79$

The lower end of the interval is the mean subtracted by M. So it is 490 - 20.79 = 469.21 hours.

The upper end of the interval is the mean added to M. So it is 490 + 20.79 = 510.79 hours.

The 95% confidence interval estimate of the population mean life of the new light-bulb is (469.21 hours, 510.79 hours).

This confidence level means that we are 95% sure that the true population mean life of the new light bulb is in this interval.