Answer:
sum of the first 12 terms of the sequence. 1, -4, -9, -14, . . = -318
Step-by-step explanation:
The given AP is,
1, -4, -9, -14, . . .
first term a = 1,
common difference d = -4 - 1 = -5
number of terms n = 12
<u>Equation:</u>
Sum of n terms of AP, S₁₂ = n/2[2a + (n - 1)d]
S₁₂ = 12/2[(2*1) + (12 - 1)*(-5)]
S₁₂ = 6[2 + (11*(-5))]
S₁₂ = 6[2 - 55] = 6*(-53) = -318
Therefore sum of the first 12 terms of the sequence. 1, -4, -9, -14, . . = -318
Answer:
2 units
Step-by-step explanation:
Since EFG and XYZ are congruent, we can write it like this:
E = X
F = Y
G = Z
Due to E and F being two units apart on the coordinate plane, we can conclude X and Y are also at a measurement of 2 units! Hope this helps!
Given that Joseph has 24 cousins, and he has 6 more females than males, the number of females will be obtained as follows;
suppose he had x males, number of females will be x+6.
The total will be:
x+(x+6)=24
x+x+6=24
2x+6=24
2x=24-6
2x=18
x=18/2
x=9
thus the number of male cousins is 9, the number of female cousins will be 9+6=15
We therefore conclude that he has 9 male cousins and 15 female cousins
