A student is trying to solve The system of two linear equations given below:

Mathematics

1 answer:

mixer [17]4 years ago

6 0

It should be , Equation Q: 8y+7z=1

You might be interested in

Please help See the picture Line A , B , C OR D ? Help

anygoal [31]

Answer:

B - Top Right

Step-by-step explanation:

3x + 6y = -57

-3x - 6y = 57

I hope this helps

3 0

3 years ago

Triangle K L J is cut by line segment N O. Line segment N O goes from side L K to side L J. The length of L N is (x minus 3) inc

kozerog [31]

Answer: x= 8

Step-by-step explanation:

According to the converse of basic proportionality theorem,

If in ΔABC , DE is a line drawn from AB to AC such that $\dfrac{AD}{DB}=\dfrac{AE}{EB}$

then, DE is parallel to the third side BC.

Applying converse of basic proportionality theorem, to get NO parallel to KJ, we must have

$\dfrac{LO}{OJ}=\dfrac{LN}{NK}\\\\\Rightarrow \dfrac{x-4}{x}=\dfrac{x-3}{x+2}\\\\\Rightarrow\ (x-4)(x+2)=x(x-3)\\\\\Rightarrow\ x^2-2x-8=x^2-3x\\\\\Rightarrow\ -2x+3x=8\\\\\Rightarrow\ x=8$

Hence, the value of x should be 8, so that Line segment N O is parallel to line segment K J.

8 0

3 years ago

Read 2 more answers

What is the smallest possible slope for a tangent without using calculus?

jekas [21]

It would probably depend on what you mean by "smallest". If it means "smallest in magnitude", then of course the smallest slope you can have is zero.

4 0

3 years ago

A proportional relationship is represented by the equation 2x=18y. If y= kx, where k is the constant of proportionality, then wh

Alik [6]

2x/2=18y/2
x=9y
x=9kx
k=1/9

3 0

3 years ago

Quadratic formula <img src="https://tex.z-dn.net/?f=%20%7B4v%7D%5E%7B2%7D%20%20-%2016v%20%2B%207%20%3D%200" id="TexFormula1"

dangina [55]

$~~~~~~~~~~~~\textit{quadratic formula} \\\\ \stackrel{\stackrel{a}{\downarrow }}{4}v^2\stackrel{\stackrel{b}{\downarrow }}{-16}v\stackrel{\stackrel{c}{\downarrow }}{+7}=0 \qquad \qquad v= \cfrac{ - b \pm \sqrt { b^2 -4 a c}}{2 a} \\\\\\ v= \cfrac{ - (-16) \pm \sqrt { (-16)^2 -4(4)(7)}}{2(4)} \implies v= \cfrac{ 16 \pm \sqrt { 256 -112}}{ 8 } \\\\\\ v=\cfrac{16\pm\sqrt{144}}{8}\implies v=\cfrac{16\pm 12}{8}\implies v= \begin{cases} \frac{7}{2}\\[1em] \frac{1}{2} \end{cases}$

5 0

3 years ago