<img src="https://tex.z-dn.net/?f=-2m-5m%3D9m-12" id="TexFormula1" title="-2m-5m=9m-12" alt="-2m-5m=9m-12" align="absmiddle" cla

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krok68 [10]

3 years ago

ss="latex-formula">

Mathematics

2 answers:

Ierofanga [76]3 years ago

7 0

Answer:

$\boxed{ \bold{ \huge{ \boxed{ \sf{m = 0.75}}}}}$

Step-by-step explanation:

$\sf{ - 2m - 5m = 9m - 12}$

Collect like terms

⇒ $\sf{ - 7m = 9m - 12}$

Move 9m to left hand side and change it's sign

⇒ $\sf{ - 7m - 9m = - 12}$

Collect like terms

⇒ $\sf{ - 16m = - 12}$

Divide both sides of the equation by -16

⇒ $\sf{ \frac{ - 16m}{ - 16} = \frac{ - 12}{ - 16} }$

Calculate

⇒ $\sf{ m = 0.75}$

Hope I helped!

Best regards!!

Blababa [14]3 years ago

6 0

Answer:

$- 2m - 5m = 9m - 12 \\ ⟶ - 2m - 5m - 9m = - 12 \\ ⟶ - 16m = - 12 \\ ⟶ - m = \frac{ - 12}{16} \\ ⟶ - m = \frac{ - 6}{8} \\ ⟶ m = - ( - \frac{6}{8} ) \\ ⟶m = \frac{6}{8}$

$m=0.75$

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BlackZzzverrR [31]

Answer:

The solution of the given trigonometric equation

$x = \frac{\pi }{6}$

Step-by-step explanation:

Step(i):-

Given

$cos( 3x - \frac{\pi }{3} ) = \frac{\sqrt{3} }{2}$

$cos( 3x - \frac{\pi }{3} ) = cos (\frac{\pi }{6} )$

$3x - \frac{\pi }{3} = \frac{\pi }{6}$

$3x - \frac{\pi }{3 } + \frac{\pi }{3} = \frac{\pi }{6} + \frac{\pi }{3}$

$3x = \frac{2\pi +\pi }{6} = \frac{3\pi }{6} = \frac{\pi }{2}$

$x = \frac{\pi }{6}$

Step(ii):-

The solution of the given trigonometric equation

$x = \frac{\pi }{6}$

verification :-

$cos( 3x - \frac{\pi }{3} ) = \frac{\sqrt{3} }{2}$

put $x = \frac{\pi }{6}$

$cos( 3(\frac{\pi }{6}) - \frac{\pi }{3} ) = \frac{\sqrt{3} }{2}$

$cos (\frac{\pi }{6} ) = \frac{\sqrt{3} }{2} \\\\\frac{\sqrt{3} }{2} = \frac{\sqrt{3} }{2}$

Both are equal

∴The solution of the given trigonometric equation

$x = \frac{\pi }{6}$

4 0

2 years ago

When Mr. Smith kicks a football, it has a vertical speed of 20 m/s, and its height, h in meters after t seconds can be modeled b

adelina 88 [10]

Answer:

look up desmos and do it on there it helps alot

Step-by-step explanation:

6 0

3 years ago

Calculate the area of the triangle with the following vertices (3, -7), (6, 4), (-2, -3)

Monica [59]

Answer:

$\boxed{\mathsf{A} \triangle = \red{\dfrac{67}{2}u.a}}$

Step-by-step explanation:

Let's follow up with the solution. Considering a triangle with the vertices $\mathsf{A(x_A, y_A)}$ , $\mathsf{B(x_B, y_B)}$ and $\mathsf{C(x_C, y_C)}$ , have a look at the representation in the cartesian plan.

From this representation we can say that the area (A) of a triangle through the knowledge of analytical geometry is given by the determinant of the vertices divided by two, mathematically,

$\mathsf{A} \triangle = \dfrac{\left| \begin{array}{ccc} \mathsf{x_A} & \mathsf{y_A }& 1 \\ \mathsf{x_B} & \mathsf{ y_B} & 1 \\ \mathsf{ x_C} & \mathsf{ y_C} & 1 \end{array} \right|}{2}$

So, applying this knowledge we're going to have,

$\mathsf{A} \triangle = \dfrac{\left| \begin{array}{ccc} 3 & -7 & 1 \\ 6 & 4 & 1 \\ -2 & -3 & 1 \end{array} \right|}{2}$

$\mathsf{A} \triangle = \dfrac{1}{2}\left[ \left.\begin{array}{ccc} 3 & -7 & 1 \\ 6 & 4 & 1 \\ -2& -3 & 1 \end{array} \right| \begin{array}{cc} 3 & -7 \\ 6 & 4 \\ -2 & -3 \end{array} \right]$