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Gekata [30.6K]
3 years ago
10

an amusement park charges $6 per student after a $72 fee. what is the total cost and how many students go to the park?

Mathematics
1 answer:
julia-pushkina [17]3 years ago
5 0
72+6x=total cost
x=number of students
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Addition and subtraction of an equilater of what?
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The population of kansas city, missouri was 435,000 in 1990 and 482,300 in 2005. if the population is changing linearly, write a
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Find the slope of the line connecting (1990,435000) and (2005,482300):

        482300-435000        47300
m = ----------------------- = ---------------- = 3153/yr (approx)
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4 0
3 years ago
A group of friends shared the cost of a printer. If John, Carl and Jason each paid $15, $25, and $112 respectively, then Carl pa
vfiekz [6]

The percent of the cost of the printer Carl paid is 16.45%

<h3>The total cost of printer</h3>

Since John, Carl and Jason each paid $15, $25, and $112 respectively, the total cost of the printer is T = $15 + $25 + $112 = $152

Since Carl paid $25, we need to find the percent of the total amount Carl paid.

<h3>Percent Carl paid</h3>

So, percent Carl paid = amount Carl paid/total cost × 100 %

Since amount Carl paid = $25 and total cost = $152,

Substituting the values of the variables into the equation, we have

percent Carl paid = amount Carl paid/total cost × 100 %

percent Carl paid = $25/$152 × 100 %

percent Carl paid = 0.1645 × 100 %

percent Carl paid = 16.45%

The percent of the cost of the printer Carl paid is 16.45%

Learn more about percent here:

brainly.com/question/24877689

6 0
2 years ago
H(x) = x2 1 k(x) = x – 2 (h k)(2) = (h – k)(3) = Evaluate 3h(2) 2k(3) =.
natima [27]

Quadratic equation is the equation in which only one variable is unknown. The highest power of the variable is 2.The value of the given functions are,

(h+k)(x)=5

(h-k)(x)=9

3h(2)+2k(3)=17

<h3>Given information-</h3>

The given function is,

h(x)=x^2+1

k(x)=x-2

<h3>Quadratic equation</h3>

Quadratic equation is the equation in which only one variable is unknown. The highest power of the variable is 2.

1) The value of the function (h+k)(2),

(h+k)(x)=h(x)+k(x)

(h+k)(x)=x^2+1+x-2

(h+k)(2)=2^2+1+2-2

(h+k)(x)=5

2)The value of the function (h-k)(3),

(h-k)(x)=h(x)-k(x)

(h-k)(x)=x^2+1-x+2

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(h-k)(x)=9

3) The value of the function 3h(2)+2k(3)

3h(x)+2k(x)=3x^2+3+2x-2\times 2

3h(2)+2k(3)=3\times2^2+3+2\times2-2\times 2

3h(2)+2k(3)=17

Hence the value of the given functions are,

(h+k)(x)=5

(h-k)(x)=9

3h(2)+2k(3)=17

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4 0
2 years ago
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