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3 years ago

PLEASE PLEASE PLEASE HELPPPP ASAPPPP!!!! best answer I’ll give brainliest :) HELP ASAP!

Mathematics

2 answers:

densk [106]3 years ago

4 0

Step-by-step explanation:

The perimer of a traingle is the saum of its sides

P = 2(3x+7) + 2(2x+2)

P= 2(3x+7) + 2*(2x+2) multiply (3x+7) and (2x+2) by 2
P= 6x+14+4x+4 add the khown values together
P=6x+4x+18 add the terms with the variable x
P= 10x+18

malfutka [58]3 years ago

3 0

10x+20 is the answer.
Since all you have to do is just add the sides lengths.

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olasank [31]

Answer: 20

Step-by-step explanation:

4 0

3 years ago

Make m<br> the subject of<br> the formula<br> r=5m²-n

KATRIN_1 [288]

Answer:

√(r+n)/5=m

Step-by-step explanation:

r=5m²-n

adding n on both sides

r+n=5m²-n+n

r+n/5=m²

taking square root on both sides

√(r+n)/5=m

5 0

3 years ago

Of 14 possible books you plan to take 8 with you on vacation how many possible coalitions of 8 could you have?

Brilliant_brown [7]

Answer:

let me think about this

Step-by-step explanation:

question i may help

7 0

3 years ago

Read 2 more answers

your total savings varies inversely with the amount spent on Bill's. if your savings is $300 when your cost of Bill's are $65. W

tatyana61 [14]

Let S and B be savings and bills respectively. Then,
S α 1/B
S = k/B Where k = Constant.
When S = $300, B = 65

Then,
300 = k/65
k = 300*65 = 19500

Therefore,
For B = $145,

S= 19500/145 = $134.48

6 0

4 years ago

Prove whether the following are identities 2tanh 1/2x / 1−tanh^2 1/2 x = sinh x

Tanzania [10]

Recall that

$\cosh^2(x) - \sinh^2(x) = 1$

Dividing both sides by cosh²(x) gives

$1 - \tanh^2(x) = \mathrm{sech}^2(x)$

Also, recall the identity

$\sinh(2x) = 2\sinh(x)\cosh(x)$

Then

$\dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = \dfrac{2\tanh\left(\frac x2\right)}{\mathrm{sech}^2\left(\frac x2\right)} \\\\ \dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = 2\tanh\left(\dfrac x2\right)\cosh^2\left(\dfrac x2\right) \\\\ \dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = 2\sinh\left(\dfrac x2\right)\cosh\left(\dfrac x2\right) \\\\\dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = \sinh(x)$

4 0

3 years ago