Given:
The two numbers are
To find:
The highest common factor (HCF) of A and B
Solution:
We have,
...(i)
All the factors of A are prime but the factors of B are not prime. So, it can be written as
...(ii)
From (i) and (ii), it is clear that 3 is the only common factor of A and B. So,
Therefore, the highest common factor (HCF) of A and B is 3.
Answer:
2
Step-by-step explanation:
Answer:
see explanation
Step-by-step explanation:
The diagrams show triangular figures
The first figure has 1 dot
The second has 1 + 2 = 3 dots
The third has 3 + 3 = 6 dots
The fourth has 6 + 4 = 10 dots
Note the pattern is + 2 , + 3, + 4
Thus the fifth pattern is 10 + 5 = 15 dots
<span>the answer is C. x ≥ 8.00 and x < 9.50
proof
</span>x ≥ 8.00 is equivalent to 8.00 ≤ x, and we have also <span>x < 9.50
so </span>x ≥ 8.00 and x < 9.50 or <span>8.00 ≤ x < 9.50</span>
Answer:
The statement, (1- <em>α</em>)% confidence interval for (μ₁ - μ₂) does not contain zero is TRUE.
Step-by-step explanation:
The hypothesis for a test is defined as follows:
<em>H</em>₀: μ₁ = μ₂ vs. <em>H</em>ₐ: μ₁ ≠ μ₂
It is provided that the test was rejected st the significance level <em>α</em>%.
If a decision is to made using the confidence interval the conditions are:
If the null hypothesis value is not included in the (1 - <em>α</em>)% confidence interval then the null hypothesis will be rejected and vice versa.
In this case the null hypothesis value is:
<em>H</em>₀: μ₁ - μ₂ = 0.
If the value 0 is not included in the (1 - <em>α</em>)% confidence interval for the difference between two means, then the null hypothesis will be rejected.
Thus the statement, (1- <em>α</em>)% confidence interval for (μ1- μ2) does not contain zero is TRUE.
