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3 years ago

Solve for b. C=b225 b=±5C√C b=±C√5 b=±5C b=±5C‾‾√

1 answer:

6 0

B=±5√c

Now if you ever need help a website you can use is cymath, i use it for my school and its how i found out your answer here, it has never been wrong for me, i'm just a student myself. Good Luck!

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a triangular prism is 20 yards long and has a triangular face with a base of 24 yards and a height of 16 yards . the other two s

lisov135 [29]

The surface area of the triangular prism is 1664 square yards.

Explanation:

Given that a triangular prism is 20 yards long and has a triangular face with a base of 24 yards and a height of 16 yards . the other two sides of the triangle are each 20 yards.

Surface area of the triangular prism:

The formula to determine the surface area of the triangular prism is

$SA=bh+Pl$

where base $b=24$ ,

height $h=16$ ,

length $l=20$ and

Perimeter $P=20+20+24=64$

Substituting these values in the above formula, we get,

$SA=(24\times 16)+(64\times 20)$

$=384+1280$

$SA=1664$

Thus, the surface area of the triangular prism is 1664 square yards.

3 0

3 years ago

An artist makes a cube-shaped sculpture.

ratelena [41]

All the sides of a cube are always the same.
Area = 12 in x 12 in = 144 in^2
Volume = 12 in x 12 in x 12 in = 1728 in^3

Hence, you can confirm all the side of this cube is 12 in.

5 0

3 years ago

Building a has 7,500 ft of an office space for 320 employees building b has 9,500 square feet of office space for 370 employees

iren2701 [21]

Answer:

I believe the correct answer is Building B

Step-by-step explanation:

Building A is 23.45 per employee and Building B is 25.67 per employee

4 0

3 years ago

Forces of 9 lbs and 13 lbs act at a 38º angle to each other. Find the magnitude of the resultant force and the angle that the re

fiasKO [112]

Answer: $R=20.84\ lb\quad 22.57^{\circ},15.43^{\circ}$

Step-by-step explanation:

Given

Two forces of 9 and 13 lbs acts $38^{\circ}$ angle to each other

The resultant of the two forces is given by

$\Rightarrow R=\sqrt{a^2+b^2+2ab\cos \theta}$

Insert the values

$\Rightarrow R=\sqrt{9^2+13^2+2(9)(13)\cos 38^{\circ}}\\\Rightarrow R=\sqrt{81+169+184.394}\\\Rightarrow R=\sqrt{434.394}\\\Rightarrow R=20.84\ lb$

Resultant makes an angle of

$\Rightarrow \alpha=\tan^{-1}\left( \dfrac{b\sin \theta}{a+b\cos \theta}\right)\\\\\text{Considering 9 lb force along the x-axis}\\\\\Rightarrow \alpha =\tan^{-1}\left( \dfrac{13\sin 38^{\circ}}{9+13\cos 38^{\circ}}\right)\\\\\Rightarrow \alpha =\tan^{-1}(\dfrac{8}{19.244})\\\\\Rightarrow \alpha=22.57^{\circ}$

So, the resultant makes an angle of $22.57^{\circ}$ with 9 lb force

Angle made with 13 lb force is $38^{\circ}-22.57^{\circ}=15.43^{\circ}$

7 0

3 years ago

Read 2 more answers

1. Which of the following is NOT an expression?

IRISSAK [1]

Answer: D, 6y + 1z = 7x - 3w

Step-by-step explanation: Expressions do not have equal signs (=), D is the correct answer.

8 0

3 years ago