All categories

2 years ago

Solve for b. C=b225 b=±5C√C b=±C√5 b=±5C b=±5C‾‾√

1 answer:

6 0

B=±5√c

Now if you ever need help a website you can use is cymath, i use it for my school and its how i found out your answer here, it has never been wrong for me, i'm just a student myself. Good Luck!

Please give me brainiest! I’m striving for the next rank!

You might be interested in

From a group of 8 people, including George and Nina, 3 people are to be selected at random to work on a certain project. What is

cestrela7 [59]

Answer: $\frac{15}{56}$

Step-by-step explanation:

We have to select george but not nina with two other people

No. of ways selecting 2 two people knowing Geroge will be the third one is

$^6C_2$ (beacuse we have to exclude Nina)

And total no of ways of selecting 3 people out of 8 people is $^8C_3$

Therefore the required Probability is $\frac{^6C_{2}}{^8C_{3}}$

= $\frac{15}{56}$

3 0

3 years ago

Find a value of 21 + 4(3^2 -5)

Svetllana [295]

the following answer to this question is 37.

7 0

2 years ago

arts and crafts shop has a bolt of crimson velvet 32 M long a customer came in during the morning and bought 120cm of the velvet

deff fn [24]

Answer:

2760

Step-by-step explanation:

I really don't know I just did 32x120

6 0

3 years ago

Consider an espresso stand with a single barista. Customers arrive at the stand at the rate of 28 per hour according to a Poisso

Snowcat [4.5K]

Answer:

The average number of customers in the system is 3.2

Step-by-step explanation:

The average number of customes in the system is given by:

$L = \frac{\lambda^{2}}{\mu(\mu - \lambda)}$

In which

$\lambda$ is the number of arirvals per time period

$\mu$ is the average number of people being served per period.

The number of arrivals is modeled by the Poisson distribution, while the service time is modeled by the exponential distribution.

Customers arrive at the stand at the rate of 28 per hour

This means that $\lambda = 28$

Service times are exponentially distributed with a service rate of 35 customers per hour.

This means that $\mu = 35$ . So

The average number of customers in the system (i.e., waiting and being served) is

$L = \frac{\lambda^{2}}{\mu(\mu - \lambda)}$

$L = \frac{28^{2}}{35(35 - 28)} = 3.2$

The average number of customers in the system is 3.2

4 0

3 years ago

PLEASE HELP DUE IN 3 minutes

son4ous [18]

Answer:

2....................

3 0

2 years ago

Read 2 more answers