Answer:x greater than -9
Step-by-step explanation:
W=A\L
Divide L from both sides
The L in the right cancels out
1. 5 and E, 6 and F, 7 and D, 8 and A, 9 and G
Sum of n terms = a1 (r^n-1/ (r-1)
Sum of first one = 3 * (4^5 - 1) / 3 = 1023
.. 2nd = 5 * (6^2 - 1) / 5 = 35
.. 3rd = 5 ^4 - 1 / 4 = 156
.. 4th = 4 * (5^4 - 1) / 4 = 624
So in increasing order its 2nd, 3rd, 4th and first.
The munimum value is, at x = 3/10, y = 5 and 10x+3y/5 = 6.
<h3>
What are nonnegative real numbers?</h3>
- Non-negative real numbers are the set of positive real numbers that are bigger than 0 (zero).
- That is, the true values are either positive or negative.
- The collection will include numbers such as 0, 1, 2, 3, 4, 5, and so on.
To find the minimum value of 10x (3y/5):
Given - y = 3/(2x)
So, we want the bare minimum of,
- = 10x + 3/5 × 3/(2x)
- = 10x + 9/(10x)
Take the derivative to obtain:
When you set it to zero, you get:
- = 100x^2 - 9 = 0
- = (10x-3)(10x+3) = 0
- = x = ± 3/10
So, at x = 3/10, y = 5 and 10x + 3y/5 = 3 + 3 = 6.
Therefore, the munimum value is, at x = 3/10, y = 5 and 10x+3y/5 = 6.
Know more about nonnegative real numbers here:
brainly.com/question/26606859
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