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lara31 [8.8K]
3 years ago
5

B. x +6 <-8 and x-1 > -1

Mathematics
1 answer:
zubka84 [21]3 years ago
5 0

Answer:

what is the question? please write a question.

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The diameter of the larger circle is 12.5 cm. The diameter of the smaller circle is 3.5 cm.
PilotLPTM [1.2K]

If the diameter of the smaller circle is 3.5cm, that means the radius is 1.75cm.

The area of the smaller circle is π × 1.75², which is ≈ 9.62112750162.

The diameter of the larger circle is 12.5 cm, so the radius would be half that, which is 6.25cm. The area of the larger circle would be π × 6.25², which is ≈ 122.718463031.

So now that we know the area of the larger circle and the smaller circle, we can find the area of the shaded region by subtracting the area of the smaller circle from the area of the larger circle, which is basically just 122.718463031 - 9.62112750162, which is = 113.097336. The closest answer here is 113.04, hence the answer is 113.04cm².

7 0
4 years ago
whats 55 + 55? I've been struggling and I can't take it anymore. I saw the memes and I need the real absolute final answer. pls
emmainna [20.7K]

Answer:

110

50+50=100

5+5=10

100+10=110

(thats how i do mental math)

5 0
2 years ago
Given that WXYZ is a rectangle and ZY=2x + 3, and WX=x +4, then WX=
omeli [17]

Answer:

7

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
A greeting card has a perimeter of 80 cm and an area of 384 square cm what are the dimensions for the greeting card
Ulleksa [173]

Step-by-step explanation:

it is a rectangle (usually).

so,

2×length + 2×width = 80

therefore, length + width = 40

length×width = 384

length = 384/width

384/width + width = 40

384 + width² = 40×width

width² - 40×width + 384 = 0

the general solution for such a square equation is

x = (-b ± sqrt(b² - 4ac))/(2a)

in our case

x = width

a = 1

b = -40

c = 384

width = (40 ± sqrt((-40)² - 4×1×384))/(2×1) =

= (40 ± sqrt(1600 - 1536))/2 =

= (40 ± sqrt(64))/2 = (40 ± 8)/2 =

= 20 ± 4

width1 = 20 + 4 = 24 cm

length1 = 40 - 24 = 16 cm

width2 = 20 - 4 = 16 cm

length2 = 40 - 16 = 24 cm

so, both solutions are the same.

the greeting card is 24×16 cm. or 16×24, depending on how you are holding it.

3 0
2 years ago
A block of wood has a mass of 3.5 kilogram. the wood has density 0.065 kg/m3
artcher [175]

Step-by-step explanation:

<u>Given </u><u>:</u><u>-</u><u> </u>

  • A block of wood has a mass of 3.5 kilogram.
  • The wood has density 0.065 kg/m³.

And we need to find out the volume of the wood. Density , volume and mass are related as ,

<u>Density </u><u>:</u><u>-</u>

  • Mass per unit Volume .

\implies\rm Density =\dfrac{Mass}{Volume}

<u>Substitute</u><u> </u><u>the </u><u>respective</u><u> values</u><u> </u><u>:</u><u>-</u><u> </u>

\implies\rm Density =\dfrac{Mass}{Volume}\\\\\rm\implies 0.065 kg/m^3=\dfrac{3.5kg}{V}\\\\\rm\implies Volume = \dfrac{3.5kg}{0.065 kg/m^3}\\\\\implies\boxed{\red{\rm Volume = 53.84 m^3}}

<u>Hence </u><u>the</u><u> </u><u>volume</u><u> is</u><u> </u><u>5</u><u>3</u><u>.</u><u>8</u><u>4</u><u> </u><u>m³</u><u> </u><u>.</u>

8 0
3 years ago
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