For #7 - part a: greatest common factor (GCF) is 5.
Part b: cross out everything BUT 10 & 20.
In a throw of 2 fair dice, there are 6*6=36 equiprobability outcomes.
To get a sum of 5, there are 4 ways, (1,4),(2,3),(3,2),(4,1) with probability of 4/36=1/9
To get at least one 5, there are 6+6-1=11 outcomes (note (5,5) has been counted in both, so subtracted from sum). The probability is 11/36
Since the two events are mutually exclusive (once we have a five, the sum can no longer be 5), we can add the probabilities to get the probability of one event or the other.
P(sum of 5 OR at least one 5)=1/9+11/36=4/36+11/36=15/36=5/9
Answer:
DUE= {0,10,12,18,19}
Step-by-step explanation:
The union of two sets is a set which contains all the elements of both the sets. thus DUE= {0,10,12,18,19}
