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Norma-Jean [14]
4 years ago
10

Write Y=5/3 x - 6/8 in standard form

Mathematics
1 answer:
ratelena [41]4 years ago
3 0

Answer:

standard form is Ax + By = C where A, B and C are all integers.

 

y=5/3x-6/8  First, multiply by LCD 24:

 

24y = 40x -18

 

40x - 24y = 18

 

Division by 2 is recommended (this is because 6/8 should have been reduced to 24, making LCD just 12):

20x - 12y = 9

 

Step-by-step explanation:

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Very true. A triangle consists of three sides so think of how u could make a triangle with those three lines
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Find the circumference of the circles below. Round your answer to the nearest whole number. Use 3.14 for Pi.
Lisa [10]

Answer:

\huge\boxed{1.\ C\approx38cm;\ 2.\ C\approx57ft;\ 3.\ C\approx50in.}

Step-by-step explanation:

The formula of a circumference of a circle:

C=2\pi r\\\\r-\text{radius}

1.\\r=6cm\\\\C=2\pi\cdot6=12\pi\\\\\pi\approx3.14\\\\C\approx12\cdot3.14=37.68\approx38(cm)\\\\2.\\r=9ft\\\\C=2\pi\cdot9=18\pi\\\\\pi\approx3.14\\\\C\approx18\cdot3.14=56.52\approx57(ft)\\\\3.\\2r=16in.\to r=8in.\\\\C=2\pi\cdot8=16\pi\\\\\pi\approx3.14\\\\C\approx16\cdot3.14=50.24\approx50(in.)

8 0
3 years ago
Write a linear equation that is parallel to
san4es73 [151]

Answer:

2y=11 - 5x

Step-by-step explanation:

An equation that is parallel shares the same gradient thus

2y= -5x - 8

y = -5/2x- 4

gradient m = -5/2

substitute value of m and the co-ordinates into a new linear equation

y = mx + c

-9 = (-5/2)(8) + c

c = 20-9 = 11

thus y = -5/2x + 11

2y=11 - 5x

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How much more did she spend in week 4 than in week 1?
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Answer:

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Step-by-step explanation:

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Find a power series for the function, centered at c. g(x) = 4x x2 2x − 3 , c = 0
BartSMP [9]

The power series for given function g(x)=\frac{4x}{(x-1)(x+3)} is g(x)=\sum{_{n=0}^\infty}~x^n(-1+(-\frac{x}{3} )^n)

For given question,

We have been given a function g(x) = 4x / (x² + 2x - 3)

We need to find a power series for the function, centered at c, for c = 0.

First we factorize the denominator of function g(x), we have:

\Rightarrow g(x)=\frac{4x}{(x-1)(x+3)}

We can write g(x) as,

\Rightarrow g(x)=\frac{1}{x-1}+\frac{3}{x+3}\\\\\Rightarrow g(x)=\frac{-1}{1-x}+\frac{1}{1+\frac{x}{3} }\\\\\Rightarrow g(x)=\frac{-1}{1-x}+\frac{1}{1-(-\frac{x}{3} )}\\

We know that, \frac{1}{1-x}=\sum{_{n=0}^\infty}~{x^n} if |x| < 1

and \frac{1}{1-(-\frac{x}{3} )}=\sum{_{n=0}^\infty}~x^n(-\frac{x}{3} )^n  if |\frac{x}{6}| < 1

\Rightarrow g(x)=-\sum{_{n=0}^\infty}~x^n+\sum{_{n=0}^\infty}~x^n(-\frac{x}{3} )^n\\     if |x| < 1 and  if |\frac{x}{6}| < 1

\Rightarrow g(x)=\sum{_{n=0}^\infty}~x^n(-1+(-\frac{x}{3} )^n) if |x| < 1

Therefore, the power series for given function g(x)=\frac{4x}{(x-1)(x+3)} is g(x)=\sum{_{n=0}^\infty}~x^n(-1+(-\frac{x}{3} )^n)

Learn more about the power series here:

brainly.com/question/11606956

#SPJ4

5 0
2 years ago
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