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Trava [24]
3 years ago
13

Renaldo increased the image size on the computer screen by 20%. By

Mathematics
1 answer:
BartSMP [9]3 years ago
3 0

Answer:

44%

Step-by-step explanation:

100 + 20 = 120/100

(1.2)^2=1.44

144 - 100 = 44%

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Alther.† Suppose a small group of 15 Allen's hummingbirds has been under study in Arizona. The average weight for these birds is
fgiga [73]

Answer:

Step-by-step explanation:

Loop

6 0
4 years ago
Suppose that you borrow $10,000 for four years at 6% toward the purchase of a car. Use PMT=
Andre45 [30]

Answer:

$234.85

Step-by-step explanation:

Payment Every Month   $234.85

Total of 48 Payments   $11,272.81

Total Interest   $1,272.81

6 0
2 years ago
Please help I need it please pleas please
monitta

Answer:

its the second one

Step-by-step explanation:

116 × 115

______

100

hope this helps

have a nice day <3

3 0
3 years ago
Read 2 more answers
Is the number a multiple of 8? Write yes or no. 4, 8, 20, 40.WHAT IS MULTIPLE
BARSIC [14]

Consider two integers x,y. We say that x is a multiple of y if x is evenly divisible by y:

\dfrac{x}{y} = k,\quad x,y,k \in \mathbb{Z}

Alternatively, we can say that x is a multiple of y if there exists an integer k such that x = ky

So:

  • 4 is not a multiple of 4, because 4/8 is not an integer.
  • 8 is a multiple of 8, because 8/8=1
  • 20 is not a multple of 8, because 20/8 is not an integer
  • 40 is a multiple of 8, because 40/8=5
8 0
3 years ago
Can you help please I am struggling thank you
Ludmilka [50]

Answer:

m<ADC = 107

Step-by-step explanation:

You need to know three things to solve this problem.

1) Opposite angles of an inscribed quadrilateral are supplementary.

2) The measure of an inscribed angle is half the measure of its subtended arc.

3) The sum of the measures of all the arcs of a circle is 360 deg.

From 1) we get:

m<A + m<C = 180

72 + m<C = 180

m<C = 108

From 2) we get:

m<C = (1/2)m(arc)BAD

108 = (1/2)[m(arc)AB + m(arc)AD]

216 = m(arc)AB + 122

m(arc)AB = 94

From 3) we get:

m(arc)AB + m(arc)BC + m(arc)CD + m(arc)DA = 360

94 + 120 + m(arc)CD + 122 = 360

m(arc)CD = 24

From 2) we get:

m<ADC = (1/2)m(arc)ABC

m<ADC = (1/2)[m(arc)AB + m(arc)BC]

m<ADC = (1/2)[94 + 120]

m<ADC = 107

3 0
3 years ago
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