Answer:
it is C 10
Step-by-step explanation:
If the positions are distinct, as in executive offices, then P(9, 5).
P(9, 5) = 9!/(9 - 5)! = 15120
If the positions are equivalent, such as seats in a legislative body, then C(9, 5).
C(9, 5) = 9!/[(9 - 5)!(5!)] = 126
Assuming the five positions are unique in their duties and responsibilities (i.e. order matters): position 1 has 9 candidates to choose from, position 2 has 8, position 3 has 7, and so on. Otherwise, if you're talking about 5 distinct but duplicate positions - meaning their responsibilities are the same but 5 people are required to carry them out - you need to divide the previous total number of possibilities by the number of ways those possibilities could have been reordered.
You only have variables, so this problem is unsolvable
Answer:
45
Step-by-step explanation:
Because if you replace the r with 3, it would be 15(3).
15(3) is the same as 15 × 3.
15 × 3 = 45
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Answer:
The answer is y=1/3x-1
Step-by-step explanation:
m=1/3
y-y=m(x-x1)
y-(-1)=1/3(x-0)
y+1=1/3x-0
-1 -1
y=1/3x-1