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Art [367]
3 years ago
9

Triangle S R Q is shown. Angle S R Q is a right angle. An altitude is drawn from point R to point T on side S Q to form a right

angle. The length of S T is 9, the length of T Q is 16, and the length of R Q is x.
What is the value of x?

12 units
15 units
20 units
24 units
Mathematics
2 answers:
lorasvet [3.4K]3 years ago
7 0

Answer:

the actual answer is 20 units

Step-by-step explanation:

Nesterboy [21]3 years ago
5 0

Answer:

20 units

Step-by-step explanation:

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What is 6 1/4 written as a decimal? Please help me I am very confused.
MrRa [10]

Answer: 6.2

Step-by-step explanation:

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Tax is 7.5%, how much tax will you pay on a suit that costs $350
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How much is 2/3 cups plus 1 1/4 cups
Schach [20]
  • Answer:

1\frac{11}{12}

  • Step-by-step explanation:

\frac{2}{3}+1\frac{1}{4}=\frac{2}{3}+\frac{5}{4}=\frac{8}{12}+\frac{15}{12}=\\    \\=\frac{8+15}{12}=\frac{23}{12}=1\frac{11}{12}

5 0
3 years ago
Rewrite the following equation in standard form. y=4x+10
Virty [35]

standard from Ax +By = C

y = 4x+10

subtract 4x from each side

-4x+y = 10

or 4x - y = -10

3 0
3 years ago
solve the system of equations by finding the reduced row-echelon form of the augmented matrix for the system of equations. x-2y+
Alekssandra [29.7K]

Answer:

x = -5, y = -6, z = -3

Step-by-step explanation:

Given the system of three equations:

\left\{\begin{array}{l}x-2y+3z=-2\\6x+2y+2z=-48\\x+4y+3z=-38\end{array}\right.

Write the augmented matrix for the system of equations

\left(\begin{array}{ccccc}1&-2&3&|&-2\\6&2&2&|&-48\\1&4&3&|&-38\end{array}\right)

Find the reduced row-echelon form of the augmented matrix for the system of equations:

\left(\begin{array}{ccccc}1&-2&3&|&-2\\6&2&2&|&-48\\1&4&3&|&-38\end{array}\right)\sim \left(\begin{array}{ccccc}1&-2&3&|&-2\\0&-14&16&|&36\\0&-6&0&|&36\end{array}\right)\sim \left(\begin{array}{ccccc}1&3&-2&|&-2\\0&16&-14&|&36\\0&0&-6&|&36\end{array}\right)

Thus, the system of three equations is

\left\{\begin{array}{r}x+3z-2y=-2\\16z-14y=36\\-6y=36\end{array}\right.

From the last equation:

y=-6

Substitute it into the second equation:

16z-14\cdot (-6)=36\\ \\16z=36-84\\ \\16z=-48\\ \\z=-3

Substitute y = -6 and z = -3 into the first equation:

x+3\cdot (-3)-2\cdot (-6)=-2\\ \\x=-2+9-12\\ \\x=-5

7 0
3 years ago
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