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galina1969 [7]
3 years ago
10

Secθ= a. (sqrt tan^2 + 1) b. 1/sinθ c. (sqrt cos^2 + 1)

Mathematics
1 answer:
Dmitry_Shevchenko [17]3 years ago
6 0

Answer:

secθ=\sqrt{ \tan^{2} θ - 1 }

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What is the answer for #7?
Karo-lina-s [1.5K]

Answer:

  • radius: 1.84 in
  • height: 3.68 in

Step-by-step explanation:

After you've worked a couple of "optimum cylinder" problems, you find that the cylinder with the least surface area for a given volume has a height that is equal to its diameter. So, the volume equation becomes ...

  V = πr²·h = 2πr³ = 39 in³

Then the radius is ...

  r = ∛(39/(2π)) in ≈ 1.83779 in ≈ 1.84 in

  h = 2r = 3.67557 in ≈ 3.68 in

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The total surface area of a cylinder is ...

  S = 2πr² + 2πrh

For a given volume, V, this becomes ...

  S = 2π(r² +r·(V/(πr²))) = 2πr² +2V/r

The derivative of this with respect to r is ...

  S' = 4πr -2V/r²

Setting this to zero and multiplying by r²/2 gives ...

  0 = 2πr³ -V

  r = ∛(V/(2π)) . . . . . . . . looks a lot like the expression above for r

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If we substitute the equation for V into the equation just above this last one, we have ...

  0 = 2πr³ - πr²·h

Dividing by πr² gives ...

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3 years ago
Amanda has 72 baseball cards this is eight times as many cards as John has how many baseball cards does John have
SVETLANKA909090 [29]
576 because 72×8=576
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Answer this volume based Question. I will make uh brainliest + 50 points​
Harlamova29_29 [7]

Answer:

\huge{\purple {r= 2\times\sqrt[3]3}}

\huge 2\times \sqrt [3]3 = 2.88

Step-by-step explanation:

  • For solid iron sphere:
  • radius (r) = 2 cm (Given)

  • Formula for V_{sphere} is given as:

  • V_{sphere} =\frac{4}{3}\pi r^3

  • \implies V_{sphere} =\frac{4}{3}\pi (2)^3

  • \implies V_{sphere} =\frac{32}{3}\pi \:cm^3

  • For cone:
  • r : h = 3 : 4 (Given)
  • Let r = 3x & h = 4x

  • Formula for V_{cone} is given as:

  • V_{cone} =\frac{1}{3}\pi r^2h

  • \implies V_{cone} =\frac{1}{3}\pi (3x)^2(4x)

  • \implies V_{cone} =\frac{1}{3}\pi (36x^3)

  • \implies V_{cone} =12\pi x^3\: cm^3

  • It is given that: iron sphere is melted and recasted in a solid right circular cone of same volume
  • \implies V_{cone} = V_{sphere}

  • \implies 12\cancel{\pi} x^3= \frac{32}{3}\cancel{\pi}

  • \implies 12x^3= \frac{32}{3}

  • \implies x^3= \frac{32}{36}

  • \implies x^3= \frac{8}{9}

  • \implies x= \sqrt[3]{\frac{8}{3^2}}

  • \implies x={\frac{2}{ \sqrt[3]{3^2}}}

  • \because r = 3x

  • \implies r=3\times {\frac{2}{ \sqrt[3]{3^2}}}

  • \implies r=3\times 2(3)^{-\frac{2}{3}}

  • \implies r= 2\times (3)^{1-\frac{2}{3}}

  • \implies r= 2\times (3)^{\frac{1}{3}}

  • \implies \huge{\purple {r= 2\times\sqrt[3]3}}
  • Assuming log on both sides, we find:

  • log r = log (2\times \sqrt [3]3)

  • log r = log (2\times 3^{\frac{1}{3}})

  • log r = log 2+ log 3^{\frac{1}{3}}

  • log r = log 2+ \frac{1}{3}log 3

  • log r = 0.4600704139

  • Taking antilog on both sides, we find:

  • antilog(log r )= antilog(0.4600704139)

  • \implies r = 2.8844991406

  • \implies \huge \red{r = 2.88\: cm}

  • \implies 2\times \sqrt [3]3 = 2.88
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-3.1, -3.5, -3.9, -3.8

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4 years ago
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3 years ago
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