Question

What is an equation of the line that is parallel to y=5x−7 and passes through (1, 11) ? Enter your equation in the box.

Answer 1

ANSWER

$y = 5x + 6$

EXPLANATION

The equation of the given line is

$y=5x-7$

This line is in the slope -intercept form,

$y = mx + c$

where

$m = 5$

is the slope.

The line which is parallel to this line and passes through (1,11) also has slope

$m = 5$

Let the equation of this line be

$y = mx + b$

This implies

$y = 5x + b$

We substitute x=1 and y=11 to get

$11 = 5(1) + b$

$b = 11 - 5 = 6$

The required equation is

$y = 5x + 6$