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Wewaii [24]
2 years ago
8

What is the value of x? 26° オー X= [?] Enter

Mathematics
2 answers:
GuDViN [60]2 years ago
4 0

Answer:

154 degrees

Step-by-step explanation:

A quadrilateral has the sum of the interior angles that is 360 degrees

for the tangent theorem we know that the angles where the lines intercept the circumference have a value of 90 degrees

x + 90 + 90 + 26 = 360

x + 206 = 360

x = 360 - 206

x = 154 degrees

Nat2105 [25]2 years ago
3 0
273 and my proof is x is the value of 1 and the answer is 273 cause 26 degrees is the value of 273
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0.985

Step-by-step explanation:

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Degger [83]

Answer:

3

Step-by-step explanation:

The computation of the mean is shown below:

= Total sum ÷ number of observations

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5 0
3 years ago
Naval intelligence reports that 4 enemy vessels in a fleet of 17 are carrying nuclear weapons. If 9 vessels are randomly targete
icang [17]

Answer:

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

Step-by-step explanation:

The vessels are destroyed without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

Fleet of 17 means that N = 17

4 are carrying nucleas weapons, which means that k = 4

9 are destroyed, which means that n = 9

What is the probability that more than 1 vessel transporting nuclear weapons was destroyed?

This is:

P(X > 1) = 1 - P(X \leq 1)

In which

P(X \leq 1) = P(X = 0) + P(X = 1)

So

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

P(X = 0) = h(0,17,9,4) = \frac{C_{4,0}*C_{13,9}}{C_{17,9}} = 0.0294

P(X = 1) = h(1,17,9,4) = \frac{C_{4,1}*C_{13,8}}{C_{17,9}} = 0.2118

Then

P(X \leq 1) = P(X = 0) + P(X = 1) = 0.0294 + 0.2118 = 0.2412

P(X > 1) = 1 - P(X \leq 1) = 1 - 0.2412 = 0.7588

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

8 0
2 years ago
Find the surface area and volume of each figure. Round each answer to the nearest hundredth.
Llana [10]

Answer: Surface area is equal to 200cm^{2}

Volume is equal to 333.33cm^{3}

Step-by-step explanation:

First, let's do surface area.

The surface area of a pyramid is equal to 1/2(perimeter of base)(lateral height) + area of the base

The perimeter of the base is 10(4) = 40; as the base is a square with a side length of 10.

The lateral height is given as 5 cm.

The area of the base is 10(10) = 100.

We can plug those numbers into the equation to get 1/2(40)(5) + 100, which comes out to be 200cm^{2}.

Now for volume.

The volume of a pyramid is equal to 1/3(area of the base)(height).

We already have the area of the base, which is 100.

The height is given as 10 cm.

Plugging those numbers into the equation, we get 1/3(100)(10), which is 1000/3 or about 333.33cm^{3}.

Hope this helps!

6 0
3 years ago
The table represents the relationship between a length measured in meters and the same length measured in kilometers.
Bess [88]

Answer:

Q1 1000     1

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   500       .5

   75   .075

   1        .001

   x       1/1000x or .001x        Q2    Y=  1/1000x

Step-by-step explanation:

just search up 1000 meters to 1 kilometer and go from there :)  

4 0
3 years ago
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