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blondinia [14]
4 years ago
12

9+9×0+9÷9 what is the answer

Mathematics
2 answers:
weqwewe [10]4 years ago
8 0
9+9=18
18 multiply 0 = 0 because whatever multiplied by zero always stays a zero 0+ 9
=9 divided by 9 will be the answer
77julia77 [94]4 years ago
6 0
The answer is one, 1
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If a bill totals 123.85 with 5% tax and 18% tip what is the total bill
lianna [129]

Answer:

$152.33

Step-by-step explanation:

123.85 x 0.05 = $6.19

123.85 x 0.18 = $22.29

123.85 + 6.19 + 22.29 = $152.33

6 0
3 years ago
Helpppp soon as possible please<br> 14) 4x - 4y= 12<br> -2x - 4y= 12
kolezko [41]
The answer is x equal 0 and y equal negative 3
3 0
3 years ago
Two interior angles in a triangle measure 101 degrees and 34 degrees. What is the measure of the third angle?
Colt1911 [192]
All the angles in a triangle equal 180 degrees.

So,

101+34+x=180

x= the missing angle.

135+x=180

Subtract both sides by 135.

x= 45

The missing angle equals 45 degrees.

I hope this helps!
~kaikers
5 0
3 years ago
The sum of nine times a number and five is one hundred eighty-five
tangare [24]

Answer:

9 x (x +5) = 185

Step-by-step explanation:

I'm pretty sure this is how you write it

4 0
3 years ago
Read 2 more answers
Please help me out :P
Veseljchak [2.6K]

cos θ = \frac{-4\sqrt{65} }{65}, sin θ = \frac{-7\sqrt{65} }{65}, cot  θ  = 4/7, sec  θ = \frac{-\sqrt{65} }{4}, cosec  θ  = \frac{-\sqrt{65} }{7}

<h3>What are trigonometric ratios?</h3>

Trigonometric Ratios are values of all the trigonometric functions based on the value of the ratio of sides in a right-angled triangle.

Sin θ: Opposite Side to θ/Hypotenuse

Tan θ: Opposite Side/Adjacent Side & Sin θ/Cos

Cos θ: Adjacent Side to θ/Hypotenuse

Sec θ: Hypotenuse/Adjacent Side & 1/cos θ

Analysis:

tan θ = opposite/adjacent = 7/4

opposite = 7, adjacent = 4.

we now look for the hypotenuse of the right angled triangle

hypotenuse = \sqrt{7^{2} + 4^{2} } = \sqrt{49+16} = \sqrt{65}

sin θ = opposite/ hyp = \frac{7}{\sqrt{65} }

Rationalize, \frac{7}{\sqrt{65} } x \frac{\sqrt{65} }{\sqrt{65} } = \frac{7\sqrt{65} }{65}

But θ is in the third quadrant(180 - 270) and in the third quadrant only tan and cot are positive others are negative.

Therefore, sin θ = - \frac{7\sqrt{65} }{65}

cos   θ  = adj/hyp = \frac{4}{\sqrt{65} }

By rationalizing and knowing that cos  θ  is negative, cos θ  = -\frac{-4\sqrt{65} }{65}

cot θ  = 1/tan θ  = 1/7/4 = 4/7

sec θ  = 1/cos θ  = 1/\frac{4}{\sqrt{65} } = -\frac{-\sqrt{65} }{4}

cosec θ  = 1/sin θ  = 1/\frac{\sqrt{65} }{7} = \frac{-\sqrt{65} }{7}

Learn more about trigonometric ratios: brainly.com/question/24349828

#SPJ1

5 0
2 years ago
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