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stepan [7]
3 years ago
13

need help.    solve for y.  try factoring first if not possible or difficult use quadratic formula.               y²-6y+6=0

Mathematics
2 answers:
shutvik [7]3 years ago
6 0
y^2-6y+6=0\\
y^2-6y+9-3=0\\
(y-3)^2=3\\
|y-3|=\sqrt3\\
y-3=\sqrt3 \vee y-3=-\sqrt3\\
y=3+\sqrt3 \vee y=3-\sqrt3
lbvjy [14]3 years ago
3 0
y^2-6y+6=0\\ \\a=1 , \ b=-6, \ c=6 \\ \\\Delta =b^2-4ac = (-6)^2 -4\cdot1\cdot6 = 36-24=12\\ \\\sqrt{\Delta }= \sqrt{12}=\sqrt{4\cdot 3}=2\sqrt{3} \\ \\x_{1}=\frac{-b-\sqrt{\Delta} }{2a}=\frac{6-2\sqrt{3}}{2 }=\frac{2( 3- \sqrt{3})}{2}= 3- \sqrt{3}

x_{2}=\frac{-b+\sqrt{\Delta} }{2a}=\frac{6+2\sqrt{3}}{2 }=\frac{2( 3+ \sqrt{3})}{2}= 3+ \sqrt{3}
 

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Forming Algebraic expressions and solving them to find the age.

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