Y = 4/5x - 1 rise over run and when x = 0 y = -1
Answer:
The correct answer is D.
Step-by-step explanation:
Given:
General equation of second degree
x² + y² + 14 x + 2 y + 14 = 0
We must transform given equation to the canonical form from which we will read requested data.
The canonical form of the circle equation is:
(x - p)² + (y - q)² = r²
Where p and q are the coordinates of the center of the circle and r are radius. (p,q) = (x,y)
x² + 2 · x ·7 + 7² - 7² + y² + 2 · y · 1 + 1 - 1 + 14 = (x+7)² + (y+1) - 49 - 1 + 14 = 0
(x + 7)² + (y + 1)² = 36
We see that p = - 7 , q = - 1 and r = 6
God with you!!!
Six hundred, eighty thousand, seven hundred and five
Answer:
(2+3)
Step-by-step explanation:
6. 8(t+2)-3(t-4)=6(t-7)+8
8t+16-3t+12=6t-42+8
8t-6t=-42+8-16-12
2t=-62
t=-62/2
t=-31
