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2 years ago

At a school assembly four out of the first 10

Mathematics

1 answer:

Ilya [14]2 years ago

5 0

Answer:

125

Step-by-step explanation:

Well if 10 x 50 is 500 (just to show how you get doesn't affect problem) you would simply divide by 4 thus, you get 125 (edit: sorry if this is wrong I'm in my first year of middle lol)

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Solve the proportion:

Sav [38]

Answer:

Cross multiply

6k+18=150

6k= 132

k=132/6

k=23.66

4 0

2 years ago

Sam bought a football jersey on sale for 40% off. He paid $30, and it was originally priced at $45 was he charged the correct am

Bond [772]

No, he should have paid $33

4 0

2 years ago

Read 2 more answers

In ΔHIJ, the measure of ∠J=90°, HI = 8 feet, and JH = 1.9 feet. Find the measure of ∠H to the nearest tenth of a degree.

artcher [175]

Answer:

21.9°

Step-by-step explanation:

In ΔHIJ, the measure of ∠J=90°, HI = 8 feet, and JH = 1.9 feet. Find the measure of ∠H to the nearest tenth of a degree.

We solve this above question using the Sine rule

a/sin A = b/sin B

In ΔHIJ, the measure of ∠J=90°, HI = 8 feet, and JH = 1.9 feet.

Hence:

HI/∠J = JH/∠H

= 8/sin 90° = 1.9/sin ∠H

Cross Multiply

∠H = arc sin(sin 1.9 × 90/8)

∠H = 21.9°

5 0

2 years ago

when a study is designed so that neither the subjects nor the experimenters know which subjects are in the treatment group and w

Nata [24]

(taken from a source)

<span>double blind
</span>
Hope this helped!

:)

5 0

3 years ago

Read 2 more answers

(Ross, 4.78) A jar contains 4 white and 4 black marbles. We randomly choose 4 marbles. If 2 of them are white and 2 are black, w

KATRIN_1 [288]

Answer:

Step-by-step explanation:

Given

Jar contains 4 white and 4 black marbles

We randomly select 4 marbles out of which 2 are white and 2 are black

Probability that 2 white and 2 black marbles are selected is

$P=\frac{^4C_2\times ^4C_2}{^8C_4}$

$P=\frac{18}{35}$

The process is continue for n trails until we choose the correct order

i.e. we have to fail in n-1 trails

For exact n selection Probability is given by

$Req.\ Probability=Probability\ of\ failure\ in\ (n-1)\ trials\times Probability\ of\ getting\ exact\ order$

$=\left ( 1-\frac{18}{35}\right )^{n-1}\times \frac{18}{35}$

8 0

3 years ago