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3 years ago

Which point lies on the graph of the finite sequence shown? 5, –1, 6, 0, 7, 1, 8

2 answers:

7 0

Hello,

$u_{1} =5\\
 u_{2} = u_{1}-6=5-6=-1\\
 u_{3} = u_{2}+7=-1+7=6\\
 u_{4} = u_{3}-6=6-6=0\\
 u_{5} = u_{4}+7=0+7=7\\
 u_{6} = u_{5}-6=7-6=1\\
 u_{7} = u_{6}+7=1+7=8\\
...\\

\boxed{ u_{2n} = u_{2n-1}-6}\\\\

\boxed{ u_{2n+1} = u_{2n}+7}\\

$

Slav-nsk [51]3 years ago

4 0

Answer:

It's (6, 1) on Edge

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3 years ago

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3 years ago

Read 2 more answers

A ladder 16 feet long is leaning against the wall of a tall building. The base of the ladder is moving away from the wall at a r

svet-max [94.6K]

Answer:

a. 0.588

b. 0.0722

c. 4.576 sqft/sec

Step-by-step explanation:

Let b and h denote the base and height as indicated in the diagram. By pythagoras theorem, $h^2 + b^2 = 16^2 = 256 \dotsc\;(1)$ because it is a right angle triangle.

It is given that $\frac{db}{dt} = 1$

Now differentiate (1) with respect to t (time) :

$\displaystyle{2h\frac{dh}{dt} + 2b\frac{db}{dt} = 0 \implies \frac{dh}{dt} = -\frac{b}{h} \frac{db}{dt}}$

$\displaystyle{=-\frac{b}{\sqrt{256 - b^2}} \frac{db}{dt} = -\frac{8}{13.856} \times 1 = -0.588}$

The minus sign indicates that the value of h is actually decreasing. The required answer is 0.588.

b. From the diagram, infer that $16 \sin{\theta} = b$ . When b = 8, then $\theta = \arcsin{0.5} = \ang{30}$ .

Differentiate the above equation w.r.t t

$\displaystyle{16 \cos{\theta} \frac{d\theta}{dt} = \frac{db}{dt} \implies \frac{d\theta}{dt} = \frac{1}{16 \cos{\theta}} = \frac{1}{13.856} = \mathbf{0.0722}}$