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Mashcka [7]
2 years ago
11

What is the surface area of this rectangular pyramid?

Mathematics
1 answer:
xz_007 [3.2K]2 years ago
5 0
Pretty sure it’s 42.5 cm.
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How to solve this equation 2+6x=1-x
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+x on each side. Then -2 on each side. Then divide both sides by 6 and you have your answer
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Species

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A

Step-by-step explanation:

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Which of the following is a characteristic of the circumcenter of a triangle? A. It is the center of the circle that can be insc
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1 year ago
Gerald buys a bag of 7,500 assorted beads online. A random sample of 150 beads contains 17 red beads. Predict the number of red
Vanyuwa [196]
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4 0
2 years ago
Line segment NY has endpoints N(-11, 5) and Y(3,-3).
777dan777 [17]

Given:

Line segment NY has endpoints N(-11, 5) and Y(3,-3).

To find:

The equation of the perpendicular bisector of NY.

Solution:

Midpoint point of NY is

Midpoint=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)

Midpoint=\left(\dfrac{-11+3}{2},\dfrac{5-3}{2}\right)

Midpoint=\left(\dfrac{-8}{2},\dfrac{2}{2}\right)

Midpoint=\left(-4,1\right)

Slope of lines NY is

m=\dfrac{y_2-y_1}{x_2-x_1}

m=\dfrac{-3-5}{3-(-11)}

m=\dfrac{-8}{14}

m=\dfrac{-4}{7}

Product of slopes of two perpendicular lines is -1. So,

m_1\times \dfrac{-4}{7}=-1

m_1=\dfrac{7}{4}

The perpendicular bisector of NY passes through (-4,1) with slope \dfrac{7}{4}. So, the equation of perpendicular bisector of NY is

y-y_1=m_1(x-x_1)

y-1=\dfrac{7}{4}(x-(-4))

y-1=\dfrac{7}{4}(x+4)

y-1=\dfrac{7}{4}x+7

Add 1 on both sides.

y=\dfrac{7}{4}x+8

Therefore, the equation of perpendicular bisector of NY is y=\dfrac{7}{4}x+8.

6 0
2 years ago
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