What do you need help with
Answer:
A and D are equal
Step-by-step explanation:
Given
![A=-2[-6, 4, 3 ,7, 12, 10]](https://tex.z-dn.net/?f=A%3D-2%5B-6%2C%204%2C%203%20%2C7%2C%2012%2C%2010%5D)
![B=3[-2, 2, 8, 8, 5, 6]](https://tex.z-dn.net/?f=B%3D3%5B-2%2C%202%2C%208%2C%208%2C%205%2C%206%5D)
![3C=3[-2, 8, 2, 5, 8, 6]](https://tex.z-dn.net/?f=3C%3D3%5B-2%2C%208%2C%202%2C%205%2C%208%2C%206%5D)
![D=-1[-12, 8, 6, 14, 24, 20].](https://tex.z-dn.net/?f=D%3D-1%5B-12%2C%208%2C%206%2C%2014%2C%2024%2C%2020%5D.)
Required
The equal matrices
First, we simplify the given expressions
![A=-2[-6, 4, 3 ,7, 12, 10]](https://tex.z-dn.net/?f=A%3D-2%5B-6%2C%204%2C%203%20%2C7%2C%2012%2C%2010%5D)
Open bracket
![A= [12, -8, -6 ,-14, -24, -20]](https://tex.z-dn.net/?f=A%3D%20%5B12%2C%20-8%2C%20-6%20%2C-14%2C%20-24%2C%20-20%5D)
Next:
![B=3[-2, 2, 8, 8, 5, 6]](https://tex.z-dn.net/?f=B%3D3%5B-2%2C%202%2C%208%2C%208%2C%205%2C%206%5D)
Open bracket
![B=[-6, 6, 24, 24, 15, 18]](https://tex.z-dn.net/?f=B%3D%5B-6%2C%206%2C%2024%2C%2024%2C%2015%2C%2018%5D)
Next:
![3C=3[-2, 8, 2, 5, 8, 6]](https://tex.z-dn.net/?f=3C%3D3%5B-2%2C%208%2C%202%2C%205%2C%208%2C%206%5D)
Divide by 3
![C=[-2, 8, 2, 5, 8, 6]](https://tex.z-dn.net/?f=C%3D%5B-2%2C%208%2C%202%2C%205%2C%208%2C%206%5D)
Lastly:
![D=-1[-12, 8, 6, 14, 24, 20].](https://tex.z-dn.net/?f=D%3D-1%5B-12%2C%208%2C%206%2C%2014%2C%2024%2C%2020%5D.)
Open bracket
![D=[12, -8, -6, -14, -24, -20].](https://tex.z-dn.net/?f=D%3D%5B12%2C%20-8%2C%20-6%2C%20-14%2C%20-24%2C%20-20%5D.)
By comparison:
![A = D=[12, -8, -6, -14, -24, -20].](https://tex.z-dn.net/?f=A%20%3D%20D%3D%5B12%2C%20-8%2C%20-6%2C%20-14%2C%20-24%2C%20-20%5D.)
Basically you multiply 78x8 which equals 624 sections.
Answer:
A = 1
B = 2
C = 14
Step-by-step explanation:
Let's say f(x) = x. Then, f(x+h) = x + h. We can use that same rule in this question.
![f(x)=x^2+14x+49\\\frac{f(x+h)-f(x)}{h}\\ \frac{[(x+h)^2+14(x+h)+49]-(x^2+14x+49)}{h}\\ \frac{x^2+hx+h^2+14x+14h+49-x^2+14x+49}{h}\\ \frac{(x^2-x^2)+2hx+h^2+(14x-14x)+14h+(49-49)}{h}\\ \frac{hx+2h^2+14h}{h}\\x+2h+14](https://tex.z-dn.net/?f=f%28x%29%3Dx%5E2%2B14x%2B49%5C%5C%5Cfrac%7Bf%28x%2Bh%29-f%28x%29%7D%7Bh%7D%5C%5C%20%5Cfrac%7B%5B%28x%2Bh%29%5E2%2B14%28x%2Bh%29%2B49%5D-%28x%5E2%2B14x%2B49%29%7D%7Bh%7D%5C%5C%20%20%5Cfrac%7Bx%5E2%2Bhx%2Bh%5E2%2B14x%2B14h%2B49-x%5E2%2B14x%2B49%7D%7Bh%7D%5C%5C%20%20%5Cfrac%7B%28x%5E2-x%5E2%29%2B2hx%2Bh%5E2%2B%2814x-14x%29%2B14h%2B%2849-49%29%7D%7Bh%7D%5C%5C%20%20%5Cfrac%7Bhx%2B2h%5E2%2B14h%7D%7Bh%7D%5C%5Cx%2B2h%2B14)
Therefore, A = 1, B = 2, C = 14