Answer:
2
Step-by-step explanation:
Thanks why do you know me
Answer: 0.1 or 1/10
Step-by-step explanation:
Answer B
Why is because Box B is near the 8 and goes on while Box A only is near 8 and stops there
Answer:
(4, -2) (see attached)
Step-by-step explanation:
Vector addition on a graph is accomplished by placing the tail of one vector on the nose of the one it is being added to. The negative of a vector is in the direction opposite to the original.
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<h3>vector components</h3>
The components of the vectors are ...
u = (1, -2)
v = (-6, -6)
Then the components of the vector sum are ...
2u -1/3v = 2(1, -2) -1/3(-6, -6) = (2 +6/3, -4 +6/3)
2u -1/3v = (4, -2)
<h3>graphically</h3>
The sum is shown graphically in the attachment. Vector u is added to itself by putting a copy at the end of the original. Then the nose of the second vector is at 2u.
One-third of vector v is subtracted by adding a vector to 2u that is 1/3 the length of v, and in the opposite direction. The nose of this added vector is the resultant: 2u-1/3v.
The resultant is in red in the attachment.
Hello! So, this question is in the form of ax² - bx - c. First thingd first, let's multiply a and c together. c = -8 and a = 5. -8 * 5 is -40. Now, let's find two factors that have a product of 40, but a sum of 18. If you list the factors, you see that 2 and 20 have a product of 40, but 2 - 20 is -18. The factors we will use are -2 and 20.
How to factor it:
For this question, you can use something called a box method and factor it by finding a factor of each column and row. Just make 4 boxes and put 5x² on the top left and -40 on the bottom left box. Put 2x on the top right box and -20x on the bottom left box. Now, factor out for each row and column. The factors should be 5x + 2 for the top part and x - 4 for the side. It should look like (5x + 2)(x - 4). Let's check it. Solve it by using the FOIL method and you get 5x² - 20x + 2x - 8. Combine like terms and you get 5x² - 18x - 8. There. The answer is B: (5x + 2)(x - 4)
Note: The box method may be challenging at first, but it can be really helpful on problems like these.
