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2 years ago

7

Help me with this plase

1 answer:

MakcuM [25]2 years ago

3 0

Answer:

I believe it is A because if you use the slope x it matches with the line.

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Question is in picture need help asap

Andrej [43]

The given expression is:

$\sqrt[4]{ 9^{ \frac{1}{2}x } }$

4th root is equivalent to raising the expression to power $\frac{1}{4}$ . So, re-writing the expression by converting radical to exponent:

$( 9^{ \frac{1}{2}x } )^{ \frac{1}{4} } \\ \\ 
= 9^{ \frac{1}{8}x }$

Therefore, the given expression simplifies to $9^{ \frac{1}{8}x }$

6 0

3 years ago

What is the answer to-8k-8(-8k+6)

Goshia [24]

-8k - 8(-8k + 6) = -8k + 64k - 48 = 56k - 48

3 0

2 years ago

What’s the correct answer

liraira [26]

I think the answer is d

7 0

2 years ago

A rectangular piece of land borders a wall. The land is to be enclosed and to be into divided 3 equal plots with 200 feet of fen

baherus [9]

Answer:

Area = 2500 square feet is the largest area enclosed

Step-by-step explanation:

A rectangular piece of land borders a wall. The land is to be enclosed and to be into divided 3 equal plots with 200 feet of fencing

Let x be the length of each box and y be the width of the box

Perimeter of the box= 3(length ) + 4(width)

$200=3x+4y$

solve for y

$200=3x+4y$

$200-3x=4y$

divide both sides by 4

$y=50-\frac{3x}{4}$

Area of the rectangle = length times width

$Area = 3x \cdot y$

$Area = 3x \cdot (50-\frac{3x}{4})$

$A=150x-\frac{9x^2}{4}$

Now take derivative

$A'=150-\frac{9x}{2}$

Set it =0 and solve for x

$0=150-\frac{9x}{2}$

$150=\frac{9x}{2}$

multiply both sides by 2/9

$x=\frac{100}{3}$

$A''=-\frac{9}{2}$

For any value of x, second derivative is negative

So maximum at x= 100/3

$A=150x-\frac{9x^2}{4}$ , replace the value of x

$A=150(\frac{100}{3})-\frac{9(\frac{100}{3})^2}{4})$

Area = 2500 square feet is the largest area enclosed

3 0

2 years ago

Line the slope and y-intercept to graph each equation below

Leno4ka [110]

Answer:

<h2>The graphs in the attachments.</h2>

Step-by-step explanation:

The slope-intercept form of an equation of a line:

$y=mx+b$

m - slope

b - y-intercept

We have the equations of the lines in the general form Ax + By + C = 0.

Convert to slope-intercept form:

8.

$2x-2y+5=0$ <em>subtract 2x and 5 from both sides</em>

$-2y=-2x-5$ <em>divide both sides by (-2)</em>

$y=x+\dfrac{5}{2}$

9.

$y-3=0$ <em>add 3 to both sides</em>

$y=3$

8.

To draw a line we need only two points. Choice any two x values and calculate the y values.

$for\ x=0\to y=0+\dfrac{5}{2}=\dfrac{5}{2}=2.5\to(0,\ 2.5)\\\\for\ x=-2\to y=-2+\dfrac{5}{2}=-2+2.5=0.5\to(-2,\ 0.5)$

9.

$y=3$

It's a horizontal line.

8 0

2 years ago