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Inessa [10]
4 years ago
6

Please help me idk this

Mathematics
2 answers:
Nata [24]4 years ago
8 0
Subtract the amount drank from the initial amount made.
Answer:
19\frac{3}{8}

kow [346]4 years ago
8 0
Lets put the 36 into 8ths because 8ths are the smallest "unit." 1 = 8/8 so if we do 36*8, we get 288. Put the 288 over the 8 to make 288/8. Now lets do the same for the 7 and 1/2 and 9 and 1/8. 7*8= 56/8. Now take the 1/2 and multiply the denominator and the numerator by 4. you get 56/8 and 4/8. Add them together. You get 60/8. Now lets do 9 and 1/8. 9*8 is 72. Put the 72 on top, 72/8. Add the 1/8 to the 72/8. You get 73/8. You now have 3 numbers. 288/8, 60/8, and 73/8. Lets arrange them the way the problem wants us to. 288/8 - 60/8 - 73/8 = X. Subtract. You get 155/8. Now how many times does 155 go into 8? About 19 times. Now lets figure out the fraction. We have 3 leftover, so 3/8. The answer is 19 and 3/8. Hope I helped and taught ya something :)
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DaniilM [7]
So the area the circle is 615.44 and the equation to solve it is 2(3.14)r^2
4 0
4 years ago
Can someone help me pls it’s due tomorrow
TiliK225 [7]

Answer:

quesion 1= 10/16 62.5%

Question 2= 6/16 37.5%

Question 3= 6/ 16 37.5%

3 0
3 years ago
Find the position function of a particle moving along a coordinate line that satisfies the given conditions. 2sint-cost
dimulka [17.4K]

Answer:

the position of a particle moving at a coordinate say(y) will satisfy the given conditions t=0 (say) if y=2sint-cost

Step-by-step explanation:

Clearly by the above we can see that if y=2sint-cost at t=0, then y=-1 because at t=0 sint vanishes and leaves us with only cost and at t=0 cos0=1

5 0
3 years ago
i have to make an expression that has a value of 10 out of the numbers 5,2,1,1 and the format it has to go in is like ( - )+( x
soldi70 [24.7K]

Answer:

(1-1)+(5×2)

hope this helps you

6 0
3 years ago
Need help with this please
Katarina [22]

Answer:

The third side is sqrt(77)

Step-by-step explanation:

Since this is a right triangle we can use the Pythagorean theorem

a^2 + b^2 = c^2 where a and b are the legs and c is the hypotenuse

2^2 + b^2 = 9^2

4+ b^2 = 81

Subtract 4 from each side

b^2 = 81-4

b^2=77

Take the square root of each side

sqrt(b^2) = sqrt(77)

b = sqrt(77)

The third side is sqrt(77)

5 0
4 years ago
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