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mart [117]
2 years ago
12

5²-64÷4 simplify and show the steps

Mathematics
1 answer:
ololo11 [35]2 years ago
8 0

Answer:

9

Step-by-step explanation:

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x-axis is for the independent variable

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Multiply the base by the exponent

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Garph x > 2. I need Help!!!!!!!!!
bija089 [108]

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where am i supposed to graph it?

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4 0
3 years ago
Fifteen percent of the workers at Nationwide Industries earn minimum wage. If 24 workers earn minimum wage, how many total worke
seropon [69]
15% = 24
100% = (100/15) * 24
= 160.

8 0
3 years ago
Read 2 more answers
The city of Omaha decided to build a new parking garage in hopes of luring more people to the Old Market district.The city will
dimulka [17.4K]

Answer:

Given:

Mean, u = 135

Sample size, n = 42

Sample mean, x' = 126

Standard deviation = 16

Significance level = 0.05

1) The null and alternative hypotheses:

H0 : u = 135 (the revenue per day is $135)

H1 : u < 135 (the revenue per day is less than $135)

2) In this case, we have a left tailed test.

Let's use the formula:

= \frac{x' - u}{s/ \sqrt{n}} = \frac{126 - 135}{16 / \sqrt{42}} = -3.645

t = - 3.645

Critical value: at a significance level of 0.05, left tailed test,

tcritical = -1.683

We reject null hypothesis, H0, since t calculated, -3.645 is less than tcritical, -1.683.

3) Given, a = 0.05, df = 41, left tailed test,

t-value = 2.02

For the corresponding confidence interval, we have:

CI = (x' - \frac{t * \sigma}{\sqrt{n}}, x' + \frac{t * \sigma}{\sqrt{n}})

CI = (126 - \frac{2.02 * 16}{\sqrt{42}}, 126 + \frac{2.02 * 16}{\sqrt{42}})

CI = (121.014, 130.986)

4) Conclusion:

We reject the estimated potential revenue advised by the consultant, H0, as it is too high, because the t-calculated falls in rejection region(i.e, less than critical value), also the upper limit of the confidence interval is less than $135.

5 0
2 years ago
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