44. 2•6= 12 and u gotta multiply that by two bc it’s 6 units on two sides of the square
same with the other side 5•2=10 and multiply that by 2
24+20= 44
I think your question is missed of key information, allow me to add in and hope it will fit the original one. Please have a look at the attached photo.
My answer:
Scale Drawing Lengths: . . / .
Actual Court Lengths . . .
Scale Factor: inch corresponds to ( ∙ ) inches, or inches, so the scale factor is .
Let = , represent the scale drawing lengths in inches, and represent the actual court lengths in inches. The -values must be converted from feet to inches.
To find actual length:
= =
() = inches, or feet
To find actual width:
= = ( )
= / ∙ /
= inches, or feet
The actual court measures feet by feet. Yes, the lot is big enough for the court Vincent planned. The court will take up the entire width of the lot.
Answer: (A) SAS (B) No (C) SSS (D) No
<u>Step-by-step explanation:</u>
A) ET ≅ MT, ∠T ≅ ∠T, TA ≅ TA ⇒ Side-Angle-Side
B) top and base are congruent, diagonal is congruent to itself, but there is no way to prove that two angles are congruent without knowing if either of the sides are parallel.
C) JU ≅ JE, UN ≅ EN, JN ≅ JN ⇒ Side-Side-Side
D) angle-angle-angle only proves similarity, not congruency
Answer:
B
Step-by-step explanation:
The sections of the parallel roads split by the transversals are in proportion, that is
=
( cross- multiply )
300 first = 577500 ( divide both sides by 300 )
first = 1925 ft
Thus
Elm st → Maple st = 1925 + 350 = 2275 ft → B
This is a basic addition/subtraction question. It's saying that they started at the 50 yard line. On the play, they gained 7 yards. So, we'll add 50+7 = 57.
They're at the 57 yard line at this point. On the second play they lost 10 yards (how unfortunate). Thereby, we will subtract 57-10=47.
50 yards +7 yards. -10 yards.
The answer will be that they'll be on the 47 yard line on the next play.