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mihalych1998 [28]
3 years ago
11

Unit Test Unit Test Active 1 2 3 4 5 6 7 CO Given fix) = 17- x2, what is the average rate of change in f(x) over the interval [1

, 5]? -6, -1/2, 1/4, 1​
Mathematics
1 answer:
sveticcg [70]3 years ago
6 0

Answer:

Step-by-step explanation:

Average rate of change is the same thing as the slope. This is a quadratic so the slope is not something that is constant like it is in a line. Here you have the x coordinates of 1 and 5; each one of these x coordinates has a y coordinate that goes with it. If we draw a line from one of these coordinates to another,  that line will have a slope. That is the slope we are trying to find. Thus, we need the y coordinates that go with each of these x coordinates. To do that, plug x into the equation and do the math to find y:

Let's start with x = 1.

f(1) = 17-(1)^2 so

f(1) = 16 and the coordinate is (1, 16).

f(5) = 17-(5)^2 so

f(5) = -8 and the coordinate is (5, -8). Now we apply the slope formula:

m=\frac{-8-16}{5-1}=\frac{-24}{4}=-6 So the answer is -6.

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<h3>What are extreme values of a function?</h3>

The extreme values of a function are either the maximum or minimum values of the function.

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The equation of a parabola in vertex form with vertex (h', k) is given by

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Since y = (x - h)² - c is the equation of a parabola in vertex form, comparing with y = a(x - h')² + k,

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Read 2 more answers
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