The required result based on given continuous functions is: 207. See the explanation for same below.
<h3>What are continuous functions?</h3>
A continuous function in mathematics is one in which a continuous variation (that is, a change without a jump) of the argument causes a continuous variation of the function's value.
<h3>What is the calculation for the above solution?</h3>
Since G and F are continuous functions,
= 19
= 35
Therefore,
![\int_{12}^{28}) \, [K g(x) - 2 f(x)] dx](https://tex.z-dn.net/?f=%5Cint_%7B12%7D%5E%7B28%7D%29%20%5C%2C%20%5BK%20g%28x%29%20-%202%20f%28x%29%5D%20dx)
= K 
So, given that K = 7, we have
7 x 35 - 2 x 19
= 245 - 38
= 207
Learn more about continuous functions at;
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(1/3) × the cone's volume = The cylinder's volume.
Step-by-step explanation:
Step 1:
The volume of any cone is obtained by multiplying
with π, the square of the radius (
) and the height (
).
So the volume of the cone,
.
Step 2:
The cylinder's volume is nearly the same as the cone but instead by multiplying
we multiply with 1.
So the cylinder's volume is determined by multiplying π with the square of the radius of the cylinder (
) and the height of the cylinder (
).
So the the cone's volume,
.
Step 3:
Now we equate both the volumes to each other.
The cone's volume : The cylinder's volume =
=
.
So if we multiply the cone's volume with
we will get the cylinder's volume with the same dimensions.
Answer:
9.42 cubic inches
Step-by-step explanation:
In order to find the volume for a sphere, we use the formula V = πr. For the sake of simplicity, we will be using 3.14 for π. Before we plug anything in, let's get our radius. Remember, the radius is half of the diameter.
Equation: d = 2r
Replace: 6 = 2r
Divide: 3 = r
Now that we have our radius, let's plug in what we have and solve.
Equation: V = 3.14r
Replace: V = 3.14(3)
Multiply: V = 9.42
Remember, volume is measured in cubic units, so use cubic inches for the unit here.
We have two points so we can find the gradient using y1-y2/x1-x2
gradient = 21-27/2-8
= 1
we know the form for any linear equation is y = mx + c
we have m and a point so we can substitute in point (2,21) to find c
21 = 1 x 2 + c
c = 19
therefore, the equation is y = x + 19