Step-by-step explanation:
Height of the cylinder A(h1)=5cm
CSA of cylinder A(CSA1)=18cm^2
Height of the cylinder B (h2)=10cm
CSA of cylinder B (CSA)=?
Since cylinder A and B are similar,
h1=xh2
or,5cm=x*10cm
or,x=1/2
Similarly,
CSA1=xCSA2
or,18cm^2=1/2*CSA2
or,CSA2=36cm^2
We khow that,
Volume of cylinder B (V2)= CSA2 * h2
=36cm^2*10cm
=36cm^3
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Answer:y=-1/2
Step-by-step explanation:
125=(1/25)^(y-1)
5^3=(5^(-2))^(y-1)
5^3=5^(-2(y-1))
The same base eliminate each other we then have
3=-2(y-1)
3=-2y+2
Collect like terms
2y=2-3
2y=-1
Divide both sides by 2
2y/2=-1/2
y=-1/2
Answer:
A) 0 (no solutions)
Step-by-step explanation:
Solve the equation:
3x - 10(x+2) = 13 - 7x
3x - 10x -20 = 13 - 7x
-7x - 20 = 13 - 7x
-20 = 13
Since both sides are clearly not equal to each other, no solution can satisfy both sides to be equal to each other. So A is correct.
Answer:
At a speed of 2 km every 3 minutes, in 2 minutes the kangaroo would travel 1,333 km.
Step-by-step explanation:
If a kangaroo hops 2 kilometers in 3 minutes, to calculate how much distance this animal hops in 2 minutes, the following calculation should be performed:
2 km / 3 min = 0.666 km per minute (2/3 x 2)
0.666 km per minute x 2 minutes = 1.333 kilometers in 2 minutes (0.666 x 2)
Therefore, at a speed of 2 km every 3 minutes, in 2 minutes the kangaroo would hop 1,333 km.
Answer:
The answer is 81
Step-by-step explanation:
All you have to do is create your long division chart with 648 inside and 8 on the outside 8 can not go into 6 but it can go into 64 so 8 goes on top of 4 you subtract 64 minus 64 becayse 8 times 8 is 64. Lastly you bring down the other 8 and 8 goes into 8 once so you put 1 on top. And so thats how you get 81.