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Margarita [4]
1 year ago
15

Write an equivalent fraction for 15 over 20 by simplifying the fractions. Reduce the following to their lowest terms. Write an e

quivalent fraction for 33 over 88 by simplifying the fractions. Reduce the following to their lowest termsWrite an equivalent fraction for81 over 120 by simplifying the fractions. Reduce the following to their lowest terms
Mathematics
1 answer:
Valentin [98]1 year ago
3 0

Equivalent fractions can be defined as fractions that may have different numerators and denominators but they represent the same value.

To get an equivalent fraction, the numerator and the denominator of one fraction are either multiplied or divided by the same constant number to produce the equivalent fraction.

Part A:

To reduce a fraction to its lowest term, we divide both the numerator and the denominator by a constant number.

Dividing both the numerator and denominator by 5

\begin{gathered} \frac{15}{20} \\ \frac{15}{20}=\frac{\frac{15}{5}}{\frac{20}{5}}=\frac{3}{4} \\ \frac{15}{20}=\frac{3}{4} \end{gathered}

Therefore, an equivalent fraction in its lowest term for

\frac{15}{20}\text{ is }\frac{3}{4}

Part B:

Dividing both the numerator and denominator by 11

\begin{gathered} \frac{33}{88} \\ \frac{33}{88}=\frac{\frac{33}{11}}{\frac{88}{11}}=\frac{3}{8} \\ \frac{33}{88}=\frac{3}{8} \end{gathered}

Therefore, an equivalent fraction in its lowest term for

\frac{33}{88}\text{ is }\frac{3}{8}

Part C:

Dividing both the numerator and denominator by 3

\begin{gathered} \frac{81}{120} \\ \frac{81}{120}=\frac{\frac{81}{3}}{\frac{120}{3}}=\frac{27}{40} \\ \frac{81}{120}=\frac{27}{40} \end{gathered}

Therefore, an equivalent fraction in its lowest term for

\frac{81}{120}\text{ is }\frac{27}{40}

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A tank contains 24 gallons of water when all of a sudden the water begins draining at a constant rate of 2 gallons per hour. Let
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Answer:

a) V(t) = 24 - 2t

b) As t increases from 3 to 6, v varies from 18 gallons to 12 gallons.

Step-by-step explanation:

The volume of the tank in terms of the time can be described by the following equation:

V(t) = V(0) - at

In which V(0) is the initial volume and a is the hourly decrease rate.

a. Write a formula that expresses v in terms of t.

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