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r-ruslan [8.4K]
3 years ago
15

If line b is perpendicular to line a, and line c is perpendicular to line a, what is the slope of line c ?

Mathematics
2 answers:
Shalnov [3]3 years ago
8 0
To answer this question, we must find the slope of line b.
 We have then:
 b = (3 - (- 2)) / (2 - (- 3))
 b = 5/5
 b = 1
 Since the lines b and c are parallel, it follows that their slopes are equal.
 Then
 mc = b = 1
 Answer:
 
The slope of line c is:
 mc = 1
just olya [345]3 years ago
8 0

Answer:  The slope of line c is given by

m_c=1.

Step-by-step explanation:  Given that line b is perpendicular to line a and  line c is perpendicular to line a.

We are to find the slope of line c.

From the graph, we see that (2, 3) and (-3, -2) are two points on the line b.

We know that

the slope of a line passing through the points (p, q) and (r, s) is given by

m=\dfrac{s-q}{r-p}.

Therefore, the slope of line b will be

m_b=\dfrac{-2-3}{-3-2}=\dfrac{5}{5}=1.

Since lines a and b are perpendicular, and the product of the slopes of two perpendicular lines is -1, so we must have

 m_b\times m_a=-1\\\\\Rightarrow 1\times m_a=-1\\\\\Rightarrow m_a=-1.

Again, lines c and a are perpendicular, so

m_a\times m_c=-1\\\\\Rightarrow -1\times m_c=-1\\\\\Rightarrow m_c=1.

Therefore, the slope of line c is given by

m_c=1.

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First, use the decay formula   A=A_oe^{kt}   where

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