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3 years ago

One number is seven less than five times another. If their sum is decreased by four the result is one. Find the numbers

1 answer:

6 0

Let the number be Y .
Y is seven
less than 5 times another (let that other be X)
Y=7-5X
sum of both Y and X minus 4 gives one
Y+X-4=1
now solve both equations .

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Solve: x - 5 = 12 A) 7 B) 16 C) 17 D) 18

postnew [5]

Answer:

The answer is option c) 17

Step-by-step explanation:

x - 5 = 12

x = 12 + 5

x = 17

The answer is c) 17

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3 years ago

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If a circle is 9 pi cm what is the radius of the circle

olganol [36]

Answer:

Step-by-step explanation:

L = 2×π×r

9π cm = 2πr

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3 years ago

During a football game a concession stand sold a family three hamburgers and two hotdogs for a total of $13 it's sold another fa

guajiro [1.7K]

Answer:

The price of each hamburger is $3

The price of each hot dogs is $2 .

Step-by-step explanation:

Given as :

The total price of 3 hamburger and 2 hot dogs = $13

The total price of 2 hamburger and 5 hot dogs = $16

Let The price of each hamburger = $x

Let The price of each hot dogs = $y

<u>Now, According to question</u>

3 x + 2 y = 13 .........A

2 x + 5 y = 16 .......B

Now, Solving to eq A and B

3 × (2 x + 5 y ) - 2 × (3 x + 2 y ) = 3 × 16 - 2 × 13

Or, (6 x + 15 y) - (6 x + 4 y) = 48 - 26

Or, (6 x - 6 x) + (15 y - 4 y) = 22

Or, 0 + 11 y = 22

∴ y = $\dfrac{22}{11}$

i.e y = $2

so, The price of each hot dogs = y = $2

<u>Now, Put the value of y into eq B</u>

i.e 2 x + 5 y = 16

or, 2 x + 5 × 2 = 16

or, 2 x = 16 - 10

or, 2 x = 6

∴ x = $\dfrac{6}{2}$

i.e x = $3

So, The price of each hamburger = x = $3

Hence, The price of each hamburger is $3 and The price of each hot dogs is $2 . Answer

3 0

3 years ago

Write an algebraic expression for “12 less than the quotient of 12 and a number z.”

algol13

$\frac{12}{n} - 12$

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3 years ago

Help pls with math lotsss of points!!!

sveticcg [70]

Answer:

5x^2+22x-12 x cannot be -5, -4, -2

(x+5)(x+4)(x+2)

Step-by-step explanation:

In order to solve this, your denominator must be the same. Let's start by writing out the two different quadratic formulas:

x^2 + 6x + 8 <-- This should factor out to (x+4)(x+2)

x^2 + 7x + 10 <-- This should factor out to (x+5)(x+2)

Now that you have factored out the two quadratics, plug them into the equation.

5x - 3

(x+4)(x+2) (x+5)(x+2)

Now as we know, -2 cannot be x because it will turn the entire equation undefined. Multiple top and bottom with (x+5) on the right side and (x+4) on the left side.

5x (x+5) - 3(x+4)

(x+5)(x+4)(x+2) (x+5)(x+4)(x+2)

Focus on the top. 5x(x+5) will turn out to be 5x^2+25x. 3(x+4) will turn out to be 3x+12. Combine the two equations because now they are equal to each other and do the subtraction:

5x^2+25x - (3x+12) = 5x^2+22x-12 x cannot be -5, -4, -2

(x+5)(x+4)(x+2) (x+5)(x+4)(x+2)

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2 years ago