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Monica [59]
3 years ago
10

One number is seven less than five times another. If their sum is decreased by four the result is one. Find the numbers

Mathematics
1 answer:
juin [17]3 years ago
6 0
Let the number be Y .
Y is seven
less than 5 times another (let that other be X)
Y=7-5X
sum of both Y and X minus 4 gives one
Y+X-4=1
now solve both equations .
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If the ratio of 7 less than a number and 7 more than the number 2, what is the number?
snow_lady [41]

Answer:


Step-by-step explanation:

I assume you mean "if the ratio of 7 less than a number and 7 more than the number is 2".

Let x be the number.

Ratio is division.

(x-7)/(x+7)=2

Multiply by (x+7) on each side:

x-7=2(x+7) = 2x+14

Add 7 on each side

x=2x+21

Subtract 2

-x=21

x=-21

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Part 1 (m + n)(x) = 5x + 4 + 6x - 9
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Part 2 (m * n)(x) = (5x + 4)(6x - 9) = 30x^2 - 21x - 36

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5 0
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A bacteria colony is quickly growing in a petri dish. The number of bacteria, y , is modeled by the function y=2(10)^2 where x i
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Tems11 [23]

Answer:

1. P(5 U 6) =2/3

2. P(2 U 5 U 6) = 5/6

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4. P(4) = 0

Step-by-step explanation:

As the number cube has 6 sides,

So,

Total outcomes = {1,2,5,5,6,6}

n(S) = 6

Now,

1. P(5U6) = P(5) + P(6)

P(5)=2/6=1/3

P(6)=2/6=1/3

P(5U6)= 1/3 + 1/3 = 2/3

2. P(2 U 5 U 6) = P(2) + P(5) + P(6)

P(2)=1/6

P(5)=2/6

P(6)=2/6

P(2 U 5 U 6) = 1/6 + 2/6 + 2/6

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3. P(1 U 2) = P(1) + P(2)

P(1) = 1/6

P(2)= 1/6

P(1 U 2) = 1/6 + 1/6

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4. P(4) = 0

As 4 is not in the outcomes, it's probability will be zero ..

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