3 years ago

One number is seven less than five times another. If their sum is decreased by four the result is one. Find the numbers

1 answer:

6 0

Let the number be Y .
Y is seven
less than 5 times another (let that other be X)
Y=7-5X
sum of both Y and X minus 4 gives one
Y+X-4=1
now solve both equations .

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