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ss7ja [257]
3 years ago
6

Find the real solutions of the equation •WILL MARK BRAINLIEST•

Mathematics
1 answer:
love history [14]3 years ago
3 0

Answer: x = ± 1.68

Step-by-step explanation:

7x^4 = 56

x^4 = 56/7

x^4 = 8

Let a = x²

(x²)² = 8

(a)² = 8

a = ± √8

Now,

a = -√8

x² = -√8 has no real solution.

Taking +√8

a = √8

x² = √8

x = ± √(√8))

x = ± 1.68

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Where is the midpoint of AB if A(6,4) and B(5,-2)?
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Answer:

Midpoint={5.5,1}

Step-by-step explanation:

M={x1+x2/2,y1+y2/2}

M={6+5/2,-2+4/2}

M={11/2,2/2}

M={5.5,1}

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Ken has a rectangular shaped vegetable garden that is 15 feet by 9 feet. He would like to increase the length and width by the s
tigry1 [53]

The current area is 15 x 9 = 135 square feet.

He wants to increase both the length and width by X:

Set up an equation:

(15 +x) * (9 +x) = 135 * 2

Simplify :

x^2 + 24x  +  135 = 270

Subtract 270 from both sides:

x^2 + 24x - 135 = 0

Use the quadratic formula to solve for x:

-24 +/- √(24^2 - 4(1*-135) / 2*1

x = 4.7 or -28.7

The answer has to be a positive value, so x = 4.7 feet.

8 0
3 years ago
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Try multiplying the original price by the decimal so for example 22.50x0.18
8 0
3 years ago
A gymnast dismounts the uneven parallel bars. Her height, h, depends on the time, t, that she is in the air h = −162 + 24t + 16.
dimulka [17.4K]
That is when h=0
so assuming yo meant
h(t)=-16t²+24t+16
solve for t such that h(t)=0
because when height=0, the gymnast hits the ground

so
0=-16t²+24t+16
using math (imma complete the square
0=-16(t²-3/2t)+16
0=-16(t²-3/2t+9/16-9/16)+16
0=-16((t-3/4)²-9/16)+16
0=-16(t-3/4)²+9+16
0=-16(t-3/4)²+25
-25=-16(t-3/4)²
25/16=(t-3/4)²
sqrt both sides
+/-5/4=t-3/4
3/4+/-5/4=t
if we do plus (because minus would give us negative height)
8/4=t
2=t
it takes 2 seconds
5 0
3 years ago
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