1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
USPshnik [31]
3 years ago
8

There are 3,784 milliliters of milk in a gallon container. How many liters are in a gallon ?

Mathematics
2 answers:
loris [4]3 years ago
7 0

3.78541 Liters are in 1 Gallon. (Or I suppose you could just say 3 Liters if they only want a whole number.) Hope this helps! ^-^

alina1380 [7]3 years ago
7 0

Answer:

3 liters and 784 milliliters left over

Step-by-step explanation:

1.   1 liter= 1000 milliliters

2.  Convert the 3000 into 3 liters

3.  784 milliliters cant make a liter so those count as left overs

You might be interested in
A recent survey by the U.S. Census Bureau determined that the median monthly housing rent was $628. If the first quartile for mo
astraxan [27]
The answer is b!! Hope this helps!
8 0
2 years ago
a woman saves $300 a month for 12 months for the next 12 months .How much does she save in total???????
Debora [2.8K]

Answer:

$3600

Step-by-step explanation:

she saves $300 a month for 12 months.

300×12=3600

hope this helps!

5 0
2 years ago
What is 2,693 divide by 56?
fgiga [73]

Answer:

the answer is 48.0892857143

7 0
3 years ago
Read 2 more answers
Please find the perimeter and area of these shapes
ladessa [460]

Answer:

ABC shaded area = 36\pi - 72   cm²

ABC shaded area perimeter = 6\pi +12\sqrt{2}    cm

ABCD area = \dfrac52 \pi  cm²

ABCD perimeter = 3\pi +2   cm

Step-by-step explanation:

<u>Shape ABC</u>

Assuming you want the area and perimeter of the shaded part of the shape only...

<u>Area</u>

Area of a sector = \dfrac12r^2\theta (where r is the radius and \theta<em> </em>

⇒ area of a sector = \dfrac12 \times 12^2\times \dfrac{\pi}{2} =36\pi  \ \textsf{cm}^2

Area of triangle = 1/2 x base x height

⇒ area of triangle = 1/2 x 12 x 12 = 72 cm²

Therefore, area of shaded area = area of sector - area of triangle

⇒ area = 36\pi - 72 cm²

<u>Perimeter</u>

Arc length = r\theta (where r is the radius and \theta<em> </em>

⇒ arc length = 12\times\dfrac12\pi =6\pi  \ \textsf{cm}

Hypotenuse of triangle = \sqrt{a^2+b^2} (where a and b are the legs of the right triangle)

⇒ hypotenuse = \sqrt{12^2+12^2} =12\sqrt{2} cm

Therefore, perimeter = arc length + hypotenuse

⇒ perimeter = 6\pi +12\sqrt{2}  cm

<u>Shape ABCD</u>

<u>Area</u>

Area of a semicircle = \dfrac12 \pi r^2 (where r is the radius)

⇒ area of large semicircle ABC = \dfrac12 \times \pi \times 2^2=2\pi  \ \textsf{cm}^2

⇒ area of small semicircle AD = \dfrac12 \times \pi \times 1^2=\dfrac12\pi  \ \textsf{cm}^2

⇒ area of shape ABCD = \dfrac12 \pi + 2 \pi=\dfrac52 \pi \ \textsf{cm}^2

<u>Perimeter</u>

1/2 circumference = \pi r

⇒ perimeter = 2\pi +2+\pi=3 \pi+2 \ \textsf{cm}

7 0
2 years ago
Sara earns $6.00 an hour more than her assistant. During an
BigorU [14]

Answer:

30 times 8 = 240 please give me Brainliest

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Other questions:
  • URGENT!!!!!!!!!!!!!!!!!!!!!!
    9·1 answer
  • My dog encountered a stray dog the other day and they both started scratching each other and then the dog left. It’s two days la
    6·1 answer
  • How to make 100 using 5 digits
    10·1 answer
  • Look at this shape:<br> Which image shows a rotation?
    15·2 answers
  • Consider the inequality -20.2 &gt; 0y. Which of the following must be true? Check all that apply.
    7·2 answers
  • Find the slope of the line that passes through (7,5) and (10,4).
    14·2 answers
  • Can you please help me fast!!!!!!!
    11·1 answer
  • Which is the correct label of the line?<br> D<br> a<br> С
    10·1 answer
  • A²- b² =<br> a² + b² =<br> (a + b)³ =
    14·1 answer
  • Please solve (show your work) <br><br> n - 5 + 3n ≠ 2n - 4
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!