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solong [7]
1 year ago
8

As an introduction to probability, a student asked to roll a fair, six sided number cube seven times the results of those seven

rolls are shown below 1,4,4,4,4,6,5 what is the standard deviation of the data?
Mathematics
1 answer:
frosja888 [35]1 year ago
3 0

Using it's concept, the standard deviation of the data is of 3.742.

<h3>What are the mean and the standard deviation of a data-set?</h3>

  • The mean of a data-set is given by the <u>sum of all values in the data-set, divided by the number of values</u>.
  • The standard deviation of a data-set is given by the square root of the <u>sum of the differences squared between each observation and the mean, divided by the number of values</u>.

For this data-set, the mean is:

M = (1 + 4 + 4 + 4 + 4 + 6 + 5)/7 = 4.

Hence the standard deviation is:

S = \sqrt{\frac{(1 - 4)^2 + (4 - 4)^2 + (4 - 4)^2 + (4 - 4)^2 + (4 - 4)^2 + (6 - 4)^2 + (5 - 4)^2}{7}} = 3.742

More can be learned about the standard deviation of a data-set at brainly.com/question/12180602

#SPJ1

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Suppose an=3an-1 -5an-2 -4an-3. and a4= -7, a5=-36, a6=-85 , find a1 , a2, a3​
maria [59]

Answer:

        a_1=4\\\\a_2=0\\\\a_3=3

Explanation:

The equation is:

      a_n=3a_{n-1}-5a_{n-2}-4a_{n-3}

and

      a_4=-7, a_5=-36, a_6=-85

<u>1. Subsittute n = 6 into the equation:</u>

      a_6=3a_{5}-5a_{4}-4a_{3}

      Now subsititute the known values:

       -85=3(-36)-5(-7)-4a_{3}

      You can solve for a_3

      -85=-108+35-4a_{3}\\\\4a_3=12\\\\a_3=12/4\\\\a_3=3

<u />

<u>2. Substitute n = 5 into the equation:</u>

    a_5=3a_{4}-5a_{3}-4a_{2}

     Substitute the known values and solve for a_2

        -36=3(-7)-5(3)-4a_{2}\\\\4a_2=-21-15+36=0\\\\a_2=0

<u>3. Substitute n = 4 into the equation, subsitute the known values and solve for </u>a_1<u />

       a_4=3a_{3}-5a_{2}-4a_{1}

        -7=3(3)-5(0)-4a_{1}\\\\4a_1=9+7=16\\\\a_1=4

7 0
3 years ago
Work out<br><img src="https://tex.z-dn.net/?f=1%20%5Cfrac%7B2%7D%7B3%7D%20-%20%20%5Cfrac%7B11%7D%7B15%7D%20%20" id="TexFormula1"
zhuklara [117]

1\dfrac{2}{3}-\dfrac{11}{15}=1\dfrac{2\cdot5}{3\cdot5}-\dfrac{11}{15}=1\dfrac{10}{15}-\dfrac{11}{15}=\dfrac{25}{15}-\dfrac{11}{15}=\dfrac{14}{15}

6 0
3 years ago
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