If 4=2^2
8=2^3
(2^)2x+10=(2^)6x
(2^)6x-(2^)2x=10
(2^)2x×7=10, where x has no real value
Answer: 9 i think, i don't know hope i helped :)
To polygons are <span>congruent when </span>their corresponding sides are equal in length and their corresponding angles are equal in measure.
so he's not true
Answer:
The answer is below
Step-by-step explanation:
We need to prove that:
(Root of Sec A - 1 / Root of Sec A + 1) + (Root of Sec A + 1 / Root of Sec A - 1) = 2 cosec A.
Firstly, 1 / cos A = sec A, 1 / sin A = cosec A and tanA = sinA / cosA.
Also, 1 + tan²A = sec²A; sec²A - 1 = tan²A

The way i did that in middle school was plot the points then find the slpoe and work it out from there