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2 years ago

Y=2x, x=y=12 how can I solve this question

1 answer:

6 0

You made a typo in your question. Please correct it if you want the correct answer.

This question would be solved using substitution.

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What equation results from completing the square and then factoring? x^2+24x=33

Nezavi [6.7K]

Answer:

Its C but the way I got is too small so I cant really give explanation

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3 years ago

Translate each phrase into an algebraic inequality:

Nonamiya [84]

Let hours = x

She can work a maximum of 30 hours so x can be any number from 30 or below.

The inequality would be: X <= 30

5 0

2 years ago

Read 2 more answers

Find the square root of 1010001 base two,leaving ur answer in base

lord [1]

(101001/4) 1/2

and can u answer my discussion

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2 years ago

Simplify. Your answer should contain only positive exponents with no fractional exponents in the denominator.

mart [117]

Answer:

$\dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}$ .

Step-by-step explanation:

The given expression is

$\dfrac{3y^{\frac{1}{4}}}{4x^{-\frac{2}{3}}y^{\frac{3}{2}}\cdot 3y^{\frac{1}{2}}}$

We need to simplify the expression such that answer should contain only positive exponents with no fractional exponents in the denominator.

Using properties of exponents, we get

$\dfrac{3}{4\cdot 3}\cdot \dfrac{y^{\frac{1}{4}}}{x^{-\frac{2}{3}}y^{\frac{3}{2}+\frac{1}{2}}}$ $[\because a^ma^n=a^{m+n}]$

$\dfrac{1}{4}\cdot \dfrac{y^{\frac{1}{4}}}{x^{-\frac{2}{3}}y^{2}}$

$\dfrac{1}{4}\cdot \dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{y^{2}}$ $[\because a^{-n}=\dfrac{1}{a^n}]$

$\dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}$

We can not simplify further because on further simplification we get negative exponents in numerator or fractional exponents in the denominator.

Therefore, the required expression is $\dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}$ .

5 0

3 years ago

Anyone know this answer?

Alexeev081 [22]

Answer:

try -8/-5 -10

Step-by-step explanation:

7 0

2 years ago