1.5 x 32 = 48 12 divided 0.03 = 400 12.8 X 3/4 ( 0.75 ) = <span>17.0666667 1.5 x 0.32 = 0 .48 1.2 divided by 0.3 = 4 AND... 102.4 divided 3.2 = 32 Hope this helps! :)
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Answer:
shift B
Step-by-step explanation:
shift a is 78.6 repeating
shift b is 79.3 repeating
mean is when you add them all then divide it by the numbers it has
The value of x is 1/13 (4th choice)
Step-by-step explanation:
![{a}^{ \frac{m}{n} } = \sqrt[n]{ {a}^{m} }](https://tex.z-dn.net/?f=%20%7Ba%7D%5E%7B%20%5Cfrac%7Bm%7D%7Bn%7D%20%7D%20%20%3D%20%20%5Csqrt%5Bn%5D%7B%20%7Ba%7D%5E%7Bm%7D%20%7D%20)
If 14^x = ¹³√14, what value of <em>x </em>makes this equation true?
![\sqrt[13]{14} = {14}^{x} \\ \sqrt[13]{14} = {14}^{ \frac{1}{13} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B13%5D%7B14%7D%20%20%3D%20%20%7B14%7D%5E%7Bx%7D%20%20%5C%5C%20%20%5Csqrt%5B13%5D%7B14%7D%20%20%3D%20%20%7B14%7D%5E%7B%20%5Cfrac%7B1%7D%7B13%7D%20%7D%20)
So, the value of <em>x</em> is 1/13 (4th choice)
<em>Hope</em><em> </em><em>it </em><em>helpful </em><em>and </em><em>useful </em><em>:</em><em>)</em>
He grates 6/8 pounds of cheese in all.
For this problem, you just have to add the numerators and keep the denominators.
4/8 + 2/8 = 6/8.
Remember, if the denominator is the same, just add the numerator.
<span><span>I think the answers are:
Statement Reason</span><span><span><span>
<span>12=<span>13</span>x+5 </span></span>Given</span><span><span>
<span>7=<span>13</span>x </span></span>Subtraction Property of Equality</span><span><span>
21 = x </span>Multiplication Property of Equality</span><span><span>
x = 21 </span><span>Symmetric Property of Equality
By the way, I'm doing the same exam for Geometry as well. There's a lot of proof questions on there which I'm not good at doing for the reasoning part. If you finish the exam before I do, maybe you can message me what the answers are for some of the questions on there so I know if my answers for the questions are incorrect or not.
Besides that, hope the answer above is correct for you.
<em>~ ShadowXReaper069</em></span></span></span></span>
