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Agata [3.3K]
4 years ago
14

A study of commuting times reports the travel times to work of a random sample of 20 employed adults in New York State. The mean

is x⎯⎯⎯ = 31.25 minutes and the sample standard deviation is s = 23.7 minutes. What is the standard error of the mean?
Mathematics
1 answer:
Elodia [21]4 years ago
5 0

Answer:

The standard error of the mean = 5.14 mins

Step-by-step explanation:

Number of random sample (n) = 20

Mean(X) = 31.25 mins

Standard deviation (α) = 23.7 mins

Standard error of mean =

standard deviation / √sample size

= 23.7/√20

= 23.7/4.4721

= 5.14 mins

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Can someone help me with this math homework please!
Korvikt [17]

Answer:

Last answer.

Step-by-step explanation:

What I do is divide the terms by the previous terms, and if they all equal 1.5, that is your answer.

5 0
3 years ago
Solve for B -(12 x 2) x (-6) = -12 x (2 x b)<br> A. -6<br> B. 6<br> C. -12<br> D. 12
myrzilka [38]

<u><em>Answer:</em></u>

<u><em>Option A</em></u>

<u><em>Step-by-step explanation:</em></u>

<u><em>-(12 x 2) x (-6) = -12 x (2 x b)</em></u>

<u><em>=> -24 x -6 = -12 x 2b</em></u>

<u><em>=> 144 = -24b</em></u>

<u><em>=> b = -6</em></u>

<u><em>Hoped this helped.</em></u>

5 0
3 years ago
Find the GCF ( Greatest Common Factor)<br><br><br>18;45<br><br><br>24;16
nika2105 [10]
18;45 = 9

24;16 = 8

I hope this helps
8 0
4 years ago
PLEASE HELP ASAP!!
BabaBlast [244]

Answer:

The first term of the sequence is -120.

Step-by-step explanation:

The formula for the "nth" term of a geometric sequence is shown below:

an = a0*r^(n-1)

Where an is the nth term, r is the ratio and n is the position of the term on the sequence. For this problem we want to find what is the initial term, a0, so we will isolate it in the formula as shown below:

a0*r^(n-1) = an

a0 = an/[r^(n-1)]

We then apply the data given to us

a0 = 31.45728/[-0.8^(7-1)]

a0 = 31.45728/[-0.8^6] =31.45728 /-0.262144= -120

The first term of the sequence is -120.

4 0
4 years ago
Write a polynomial function of minimum degree in standard form with real coefficients whose zeros and their multiplicities inclu
Softa [21]

<u>Answer-</u>

<em>The polynomial function is,</em>

y=x^4-10x^3+38x^2-64x+40

<u>Solution-</u>

The zeros of the polynomial are 2 and (3+i). Root 2 has multiplicity of 2 and (3+i) has multiplicity of 1

The general form of the equation will be,

\Rightarrow y=(x-(2))^2(x-(3+i))(x-(3-i))   ( ∵ (3-i) is the conjugate of (3+i) )

\Rightarrow y=(x-2)^2(x-3-i)(x-3+i)

\Rightarrow y=(x^2-4x+4)((x-3)-i)((x-3)+i)

\Rightarrow y=(x^2-4x+4)((x-3)^2-i^2)

\Rightarrow y=(x^2-4x+4)((x^2-6x+9)+1)

\Rightarrow y=(x^2-4x+4)(x^2-6x+10)

\Rightarrow y=x^2x^2-6x^2x+10x^2-4x^2x+4\cdot \:6xx-4\cdot \:10x+4x^2-4\cdot \:6x+4\cdot \:10

\Rightarrow y=x^4-10x^3+14x^2+24x^2-40x-24x+40

\Rightarrow y=x^4-10x^3+38x^2-64x+40

Therefore, this is the required polynomial function.


4 0
4 years ago
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